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php微信公众开发之获取周边酒店信息的方法_php技巧

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Release: 2016-05-16 20:27:49
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本文实例讲述了php微信公众开发之获取周边酒店信息的方法。分享给大家供大家参考。具体分析如下:

关注微信公众之后发送回复地理位置信息,即可回复周边附近的酒店信息列表,下面我就来给各位介绍利用php是怎么实现这个功能,希望全子对大家有帮助.代码如下:

复制代码 代码如下:
 //将提交过来的信息接收
$signature = $_GET['signature'];
 $timestamp = $_GET['timestamp'];
 $nonce = $_GET['nonce'];
 $echostr = $_GET['echostr'];
 $token = "jb51.net";
 //判断接入网站
 
 //进行字典排序
 $arr = array($token,$timestamp,$nonce);
 
 sort($arr);
 
 //完成字符串的拼接和sha1加密
 $result = sha1(join($arr));
 //判断生成的字符串和$signature是否相等,如果相等,直接输出$echostr,这样网站接入成功
 if($result==$signature){
 echo $echostr;
 }
 
 //接收微信公众账号接收到的信息
 $poststr = $GLOBALS["HTTP_RAW_POST_DATA"];
 
 $xmlObj = simplexml_load_string($poststr,'SimpleXMLElement',LIBXML_NOCDATA);
 $ToUserName = $xmlObj->ToUserName;
 $FromUserName = $xmlObj->FromUserName;
 $CreateTime = $xmlObj->CreateTime;
 $MsgType = $xmlObj->MsgType;
 $Content = $xmlObj->Content;
 
 if($MsgType=='location'){
 $Location_X = $xmlObj->Location_X;
 $Location_Y = $xmlObj->Location_Y;
 $Scale = $xmlObj->Scale;
 $Label = $xmlObj->Label;
 
 $urlstr = "http://api.map.baidu.com/place/v2/search?&query=酒店&location=".$Location_X.",".$Location_Y."&radius=5000&output=json&ak=DESY8unmZnUlLB0mlowjuiRr";  //此处ak参数需要个人的百度开发序列号,自己去百度申请下就好了
 $jsonstr = file_get_contents($urlstr);
 $json = json_decode($jsonstr,true);
 
 $pic_640 = "http://api.map.baidu.com/staticimage?width=640&height=320¢er=".$Location_Y.",".$Location_X."&zoom=15&markers=".$Location_Y.",".$Location_X."&markerStyles=l,";
 $pic_80 = "http://api.map.baidu.com/staticimage?width=80&height=80¢er=".$Location_Y.",".$Location_X."&zoom=15&markers=".$Location_Y.",".$Location_X."&markerStyles=l,";
 $p_640 = file_get_contents($pic_640);
 file_put_contents('./images/640_'.$FromUserName.".png",$p_640);
 $p_80 = file_get_contents($pic_80);
 file_put_contents('./images/80_'.$FromUserName.".png",$p_80);
 echo pic_send($json['results']);
 }
 function pic_send($arr){
 global $ToUserName,$FromUserName;
 $str = "
 
 
 ".time()."
 
 ".count($arr)."
 ";
 foreach($arr as $k=>$v){
 if($k==0){
 $picurl = "http://jb51.net/weixin/images/640_".$FromUserName.".png";
 }else{
 $picurl = "http://jb51.net.net/weixin/images/80_".$FromUserName.".png";
 }
 $str .="
 
 
 
 
 
 
";
 }
 $str .= "
";
 return $str;
 }
?>

希望本文所述对大家的php程序设计有所帮助。

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