In a recent project, I needed to check the size of the data user table, including the number of records and the amount of disk space occupied. I have been searching online for a long time to check the space occupied by each table in the MSSQL database. It is relatively okay.
However, methods 2 and 3 return a lot of data, some of which are data we don’t care about. I did the test on AdventureWorks2012 data. The code for the second method is as follows:
Copy code The code is as follows:
View Code
if not exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[tablespaceinfo]') and OBJECTPROPERTY(id, N'IsUserTable') = 1)
create table tablespaceinfo --Create result storage table
( nameinfo varchar(50) ,
rowsinfo int , reserved varchar(20) ,
datainfo varchar(20) ,
index_size varchar(20) ,
unused varchar(20) )
delete from tablespaceinfo --Clear data table
declare @tablename varchar(255) --Table name
declare @cmdsql varchar(500)
DECLARE Info_cursor CURSOR FOR
select o.name
from dbo. sysobjects o where OBJECTPROPERTY(o.id, N'IsTable') = 1
and o.name not like N'#%%' order by o.name
OPEN Info_cursor
FETCH NEXT FROM Info_cursor
INTO @tablename
WHILE @@FETCH_STATUS = 0
BEGIN
if exists (select * from dbo.sysobjects where id = object_id(@tablename) and OBJECTPROPERTY(id, N'IsUserTable') = 1)
execute sp_executesql
N'insert into tablespaceinfo exec sp_spaceused @tbname',
N'@tbname varchar(255)',
@tbname = @tablename
FETCH NEXT FROM Info_cursor
INTO @tablename
END
CLOSE Info_cursor
DEALLOCATE Info_cursor
GO
--itlearner Note: Display database information
sp_spaceused @updateusage = 'TRUE'
--itlearner Note: Display table information
select *
from tablespaceinfo
order by cast(left(ltrim(rtrim(reserved)), len(ltrim(rtrim(reserved)))-2) as int) desc
The running effect is as follows:
Obviously this return result is wrong. But it provides an idea.
The modified SQL statement is as follows:
Copy the code The code is as follows:
View Code
IF NOT EXISTS ( SELECT *
FROM sys.tables
WHERE name = 'tablespaceinfo' )
BEGIN
CREATE TABLE tablespaceinfo --创建结果存储表
(
Table_Name VARCHAR(50) ,
Rows_Count INT ,
reserved INT ,
datainfo INT ,
index_size INT ,
unused INT
)
END
DELETE FROM tablespaceinfo
--清空数据表
CREATE TABLE #temp --创建结果存储表
(
nameinfo VARCHAR(50) ,
rowsinfo INT ,
reserved VARCHAR(20) ,
datainfo VARCHAR(20) ,
index_size VARCHAR(20) ,
unused VARCHAR(20)
)
DECLARE @tablename VARCHAR(255)
--表名称
DECLARE @cmdsql NVARCHAR(500)
DECLARE Info_cursor CURSOR
FOR
SELECT '[' + TABLE_SCHEMA + '].[' + TABLE_NAME + ']' AS Table_Name
FROM [INFORMATION_SCHEMA].[TABLES]
WHERE TABLE_TYPE = 'BASE TABLE'
AND TABLE_NAME <> 'tablespaceinfo'
OPEN Info_cursor
FETCH NEXT FROM Info_cursor
INTO @tablename
WHILE @@FETCH_STATUS = 0
BEGIN
SET @cmdsql = 'insert into #temp exec sp_spaceused ''' + @tablename
+ ''''
EXECUTE sp_executesql @cmdsql
FETCH NEXT FROM Info_cursor
INTO @tablename
END
CLOSE Info_cursor
DEALLOCATE Info_cursor
GO
--itlearner注:显示数据库信息
--sp_spaceused @updateusage = 'TRUE'
--itlearner注:显示表信息
UPDATE #temp
SET reserved = REPLACE(reserved, 'KB', '') ,
datainfo = REPLACE(datainfo, 'KB', '') ,
index_size = REPLACE(index_size, 'KB', '') ,
unused = REPLACE(unused, 'KB', '')
INSERT INTO dbo.tablespaceinfo
SELECT nameinfo ,
CAST(rowsinfo AS INT) ,
CAST(reserved AS INT) ,
CAST(datainfo AS INT) ,
CAST(index_size AS INT) ,
CAST(unused AS INT)
FROM #temp
DROP TABLE #temp
SELECT Table_Name ,
Rows_Count ,
CASE WHEN reserved > 1024
THEN CAST(reserved / 1024 AS VARCHAR(10)) + 'Mb'
ELSE CAST(reserved AS VARCHAR(10)) + 'KB'
END AS Data_And_Index_Reserved ,
CASE WHEN datainfo > 1024
THEN CAST(datainfo / 1024 AS VARCHAR(10)) + 'Mb'
ELSE CAST(datainfo AS VARCHAR(10)) + 'KB'
END AS Used ,
CASE WHEN Index_size > 1024
THEN CAST(index_size / 1024 AS VARCHAR(10)) + 'Mb'
ELSE CAST(index_size AS VARCHAR(10)) + 'KB'
END AS index_size ,
CASE WHEN unused > 1024 THEN CAST(unused / 1024 AS VARCHAR(10)) + 'Mb'
ELSE CAST(unused AS VARCHAR(10)) + 'KB'
END AS unused
FROM dbo.tablespaceinfo
ORDER BY reserved DESC
The running result is as shown in the figure:
At the same time, his third method returns too much data, a lot of which we don’t care much about. Yes, the original SQL statement is as follows:
Copy code The code is as follows:
View Code
SELECT OBJECT_NAME(id) tablename ,
* reserved / 1024 reserved ,
RTRIM(8 * dpages / 1024) + 'Mb' used ,
* ( reserved - dpages ) / 1024 unused ,
* dpages / 1024 - rows / 1024 * minlen / 1024 free ,
rows
FROM sysindexes
WHERE indid = 1
ORDER BY reserved DESC
The running result is as shown in the figure:
This contains some index information. In fact, we only care about the disk information occupied by the table.
The modified SQL statement is as follows:
Copy code The code is as follows:
View Code
SELECT OBJECT_NAME(id) tablename ,
CASE WHEN reserved * 8 > ; 1024 THEN RTRIM(8 * reserved / 1024) + 'MB'
ELSE RTRIM(reserved * 8) + 'KB'
END DataReserve ,
CASE WHEN dpages * 8 > 1024 THEN RTRIM( 8 * dpages / 1024) + 'MB'
ELSE RTRIM(dpages * 8) + 'KB'
END Used ,
CASE WHEN 8 * ( reserved - dpages ) > 1024
THEN RTRIM( 8 * ( reserved - dpages ) / 1024) + 'MB'
ELSE RTRIM(8 * ( reserved - dpages )) + 'KB'
END unused ,
CASE WHEN ( 8 * dpages / 1024 - rows / 1024 * minlen / 1024 ) > 1024
THEN RTRIM(( 8 * dpages / 1024 - rows / 1024 * minlen / 1024) '
ELSE RTRIM(( 8 * dpages / 1024 - rows / 1024 * minlen / 1024 ))
+ 'KB'
END FREE ,
rows AS Rows_Count
FROM sys.sysindexes
W HERE indid = 1
AND status = 2066 -- status='18'
ORDER BY reserved DESC
The running results are as follows:
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http://www.bkjia.com/PHPjc/327781.htmlwww.bkjia.comtruehttp: //www.bkjia.com/PHPjc/327781.htmlTechArticleIn recent projects, I need to check the size of the data user table, including the number of records and the amount of disk space occupied. I have been searching online for a long time to check the space occupied by each table in the MSSQL database...