How to construct JSON format and new array with PHP data set_PHP tutorial

I wrote a function to convert the PHP result set into JSON format. You can call it directly:

Copy the code The code is as follows:

function RecordToJson($recordset)
{
$jstr='[';
while($rs = $recordset->Fetch())
{
//$ nick = iconv("GBK",'utf-8',$rs['nick']);/*Convert to utf-8 encoding*/
//TODO: Traverse the result set
$arr_keys=array_keys ($rs);
$jstr=$jstr.'{';
for($i=0;$i{
/ /The database encoding is gbk, the encoding needs to be converted
//TODO;iconv("GBK",'utf-8',$rs['nick']);/*Convert to utf-8 encoding*/
$key=iconv("GBK",'utf-8',$arr_keys[$i]);//$arr_keys[$i];
$value=iconv("GBK",'utf-8', $rs[$arr_keys[$i]]);//$rs[$arr_keys[$i]];
$jstr=$jstr.'"'.$key.'":"'.$value. '",';
}
$jstr=substr($jstr,0,strlen($jstr)-1);
$jstr=$jstr.'},';
}
$jstr=substr($jstr,0,strlen($jstr)-1);
$jstr=$jstr.']';
return $jstr;
}

PHP’s default result set array has a numeric index. The following function can remove the numeric index and only keep the field index:

Copy code The code is as follows:

function RebuilderRecord($recordset)
{
$row=0;
while($rs = $recordset->Fetch())
{
//TODO: Traverse the result set
$arr_keys=array_keys($rs);
for($i=0;$i{
$newrs[$row][$arr_keys[$i]]=$rs[$arr_keys[$i]];
}
$row++;
}
return $newrs;
}

http://www.bkjia.com/PHPjc/326137.htmlwww.bkjia.comtruehttp: //www.bkjia.com/PHPjc/326137.htmlTechArticleI wrote a function to convert the PHP result set into JSON format, which can be called directly: Copy the code The code is as follows: function RecordToJson($recordset) { $jstr='['; while($rs = $recordset-Fetc...