A few days ago, I wrote an article about how to get the URL after Baidu jump. After searching on Baidu, someone also studied Baidu link?url=.
The following results are roughly obtained:
1. The encryption method is based on: random + input residence time + snapshot address for encryption
2. There should be three elements in the entire code Parts: 1. Time of search term; 2. Search keywords; 3. Randomly generated unique identification code.
3. In any environment or browser url = there is a similar code at the end
From the above results of other people's research, we can know that "there is a similar code at the end" is more usable, so we will start with this.
I searched for "enenba" and found that the URL of my first search result had the same code, which was
http://www.baidu.com/link?url=………… ebac5573358cc3c0659257bfcf54763ec1c5ecff3b3fbd1d4c
All search results have a piece of code ebac5573358cc3c0659257bfcf54 (found after searching N times)
The 763ec1c5ecff3b3fbd1d4c at the end looks like the search result Real URL. (It has been verified that it is the ciphertext of the real URL)
I verified it like this:
1. First search www.php100.com on Baidu
The first result link:
http://www. baidu.com/link?url=…………ebac5573358cc3c0659257bfcf546427d385fef6656de2404d6843da27
See the first few 6427d385fef6656de2404d6843da27
2. Search www.hao123.com on Baidu
First result link:
http: //www.baidu.com/link?url=…………ebac5573358cc3c0659257bfcf54 6427d385e6ff7a6de0434d6843da
See the first few 6427d385e6ff7a6de0434d6843da
……
After searching N websites many times, I found that the first few domain names Yes For "www.", the ciphertext is 6427d385
and www. is four characters, and the ciphertext 6427d385 is eight characters. You can know that two characters of the ciphertext are equal to one character of the URL.
So I wrote a php form query and got the ciphertext part for easy viewing later.
Publish the php source code:
Copy the code The code is as follows:
Query Baidu link?ulr=Real link form</ title> <br></head> <br><body> <br><?php <BR>/* <BR>getrealurl Get the URL address after 301 and 302 redirection by enenba.com <BR> @param str $url Query <BR>$return str The real url of the directed url <BR>*/ <BR>function getrealurl($url){ <BR>$header = get_headers($url,1); <BR>if (strpos($header[0],'301') || strpos($header[0],'302')) { <BR>if(is_array($header['Location'])) { <BR>return $header['Location'][count($header['Location'])-1]; <BR>}else{ <BR>return $header['Location']; <BR>} <BR>} else { <BR>return $url; <BR>} <BR>} <BR>$input = '<form method="get" action=""><input type="text" name="url " id="url" style="width:800px;" /><input type="submit" value="Submit" /></form><body></html>'; <br>$url = isset($_GET['url'])?$_GET['url']:''; <br>if(empty($url)) exit($input); <br>$urlreal = getrealurl($url); <br>echo 'The real url is:'.$urlreal; <br>$urlreal = ltrim($urlreal,'http://'); <br>$search = '/ebac5573358cc3c0659257bfcf54( [0-9a-f]+)/i'; <br>preg_match($search,$url,$r); <br>$url_encode = $r[1]; unset($r); <br>echo '<br/>The ciphertext part is: '.$url_encode.'<br/>'; <br>$urlreal_arr = str_split($urlreal); <br>$url_encode_arr = str_split($url_encode,2 ; Research to be continued. . . . <br>This site declares in advance: The articles on cnbeta are not published by me. My analysis is only based on my own ideas and research. It is just a process. As for whether there are results, I have my own conclusions. Please don't rant. <br>Continuing from the previous article, I carefully looked at the long code of the Baidu result URL and found that the ciphertext only consists of numbers and letters a to f, which is a hexadecimal code. <br>Hexadecimal is from 0->1->2->3->4->5->7->8->9->a->b ->c->d->e->f <br>I collected a series of URLs and counted the first code. </div>ebac5573358cc3c0659257bfcf54XX... <br>The url corresponding to the XX code is as follows <br><br><br><br>Copy the code<br><br> The code is as follows:<br><div class="codebody" id="code98723"> <br>33 0 23 @ 13 P 03 ` 73 p 63 <br>! 32 1 22 A 12 Q 02 a 72 q 62 <br>" 31 2 21 B 11 R 01 b 71 r 61 <br> # 30 3 20 C 10 S 00 c 70 s 60 <br>$ 37 4 27 D 17 T 07 d 77 t 67 <br>% 36 5 26 E 16 U 06 e 76 u 66 <br>& 35 6 25 F 15 V 05 f 75 v 65 <br>' 34 7 24 G 14 W 04 g 74 w 64 <br>( 3b 8 2b H 1b X 0b h 7b x 6b <br>) 3a 9 2a I 1a Y 0a i 7a y 6a <br>* 39 : 29 J 19 Z 09 j 79 z 69 <br>+ 38 ; 28 K 18 [ 08 k 78 { 68 <br>, 3f < 2f L 1f 0f l 7f | 6f <BR> - 3e = 2e M 1e ] 0e m 7e } 6e <BR>. 3d > 2d N 1d ^ 0d n 7d ~ 6d <br>/ 3c ? 2c O 1c _ 0c o 7c 6c <br>
</div> <br>It is found that it should be a character in an ascii code table, but the order should be confused. But it is all like this in one base: <br>3->2->1->0-> 7->6->5->4->b->a->9->8->f->e->d->c <br>four digits In descending order, it can be seen that the overall trend is decreasing. <br>But what I don’t understand is that the corresponding 0c and 73 are adjacent in ascii. There is no way. I can’t see the pattern. Let’s look at the second one. The code for this bit is <br>ebac5573358cc3c0659257bfcf54XXYY. The url corresponding to the bit code for <br>YY is as follows: <br><div class="codetitle"> <span style="CURSOR: pointer" onclick="doCopy('code76697')"><u>70 0 60 @ 50 P 40 ` 30 p 20 </u>! 71 1 61 A 51 Q 41 a 31 q 21 </span>" 72 2 62 B 52 R 42 b 32 r 22 </div># 73 3 63 C 53 S 43 c 33 s 23 <div class="codebody" id="code76697">$ 74 4 64 D 54 T 44 d 34 t 24 <br>% 75 5 65 E 55 U 45 e 35 u 25 <br>& 76 6 66 F 56 V 46 f 36 v 26 <br>' 77 7 67 G 57 W 47 g 37 w 27 <br>( 78 8 68 H 58 X 48 h 38 x 28 <br>) 79 9 69 I 59 Y 49 i 39 y 29 <br>* 7a : 6a J 5a Z 4a j 3a z 2a <br>+ 7b ; 6b K 5b [ 4b k 3b { 2b <br>, 7c < 6c L 5c 4c l 3c | 2c <BR>- 7d = 6d M 5d ] 4d m 3d } 2d <BR>. 7e > 6e N 5e ^ 4e n 3e ~ 2e <br>/ 7f ? 6f O 5f _ 4f o 3f 2f <br><br> <br>The secret text of the second group follows the increasing order of hexadecimal. <br>0->1->2->3->4->5->7->8->9->a->b->c-> ;d->e->f <br>The overall trend is decreasing. <br>Look at the third group <br>ebac5573358cc3c0659257bfcf54XXYYZZ. . . . </div>The url corresponding to the ZZ code is as follows: <br><br><br><br> Copy the code <br><br> The code is as follows: <br><div class="codetitle"> <span style="CURSOR: pointer" onclick="doCopy('code16218')">84 0 94 @ a4 P b4 ` c4 p d4 <u>! 85 1 95 A a5 Q b5 a c5 q d5 </u>" 86 2 96 B a6 R b6 b c6 r d6 </span># 87 3 97 C a7 S b7 c c7 s d7 </div>$ 80 4 90 D a0 T b0 d c0 t d0 <div class="codebody" id="code16218">% 81 5 91 E a1 U b1 e c1 u d1 <br>& 82 6 92 F a2 V b2 f c2 v d2 <br> ' 83 7 93 G a3 W b3 g c3 w d3 <br>( 8c 8 9c H ac ae Z be j ce z de <br>+ 8f ; 9f K af [ bf k cf { df <br>, 88 < 98 L a8 b8 l c8 | d8 <BR>- 89 = 99 M a9 ] b9 m c9 } d9 <BR>. 8a > 9a N aa ^ ba n ca ~ da <br>/ 8b ? 9b O ab _ bb o cb db <br><br> <br>Does not explain the upper order: <br> 4->5->6->7->0->1->2->3->4->c->b->e->f- >8->9->a->b <br>Overall, it is increasing <br> I haven’t looked at the following digits, but I can probably tell that it is a group of four digits. Hexadecimal confusion , as for whether it is increasing or decreasing, a certain amount of data is needed to determine. <br>To be continued.
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<br>http://www.bkjia.com/PHPjc/326056.html<br><br>www.bkjia.com<br><br>true<br>http: //www.bkjia.com/PHPjc/326056.html<p align="left"></p>
<div style="display:none;">TechArticle<span id="url" itemprop="url"></span>A few days ago I wrote an article on how to get the URL after Baidu jump. I checked it on Baidu. Some people have also studied Baidu link?url=. The following results are roughly obtained: 1. The encryption method is based on...<span id="indexUrl" itemprop="indexUrl"></span><span id="isOriginal" itemprop="isOriginal"></span>
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<a href="https://www.php.cn/faq/734010.html" title="After 2 months, the humanoid robot Walker S can fold clothes" class="phphistorical_Version2_mids_title">After 2 months, the humanoid robot Walker S can fold clothes</a>
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<a href="https://www.php.cn/faq/755834.html" title="C++ function parameter type safety check" class="phphistorical_Version2_mids_title">C++ function parameter type safety check</a>
<span class="Articlelist_txts_time">Apr 19, 2024 pm 12:00 PM</span>
<p class="Articlelist_txts_p">C++ parameter type safety checking ensures that functions only accept values of expected types through compile-time checks, run-time checks, and static assertions, preventing unexpected behavior and program crashes: Compile-time type checking: The compiler checks type compatibility. Runtime type checking: Use dynamic_cast to check type compatibility, and throw an exception if there is no match. Static assertion: Assert type conditions at compile time.</p>
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<span class="Articlelist_txts_time">Jun 04, 2024 pm 08:01 PM</span>
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<a href="https://www.php.cn/faq/780152.html" title="Baidu Robin Li led a team to visit PetroChina to discuss the intelligence of the oil and gas industry" class="phphistorical_Version2_mids_title">Baidu Robin Li led a team to visit PetroChina to discuss the intelligence of the oil and gas industry</a>
<span class="Articlelist_txts_time">May 07, 2024 pm 06:13 PM</span>
<p class="Articlelist_txts_p">According to news from this site on May 7, on May 6, Robin Li, founder, chairman and CEO of Baidu, led a team to visit China National Petroleum Corporation (hereinafter referred to as "PetroChina") in Beijing and met with directors of China National Petroleum Corporation Chairman and Party Secretary Dai Houliang held talks. The two parties had in-depth exchanges on strengthening cooperation and promoting the deep integration of the energy industry with digital intelligence. PetroChina will accelerate the construction of a digital China Petroleum Corporation, strengthen cooperation with Baidu Group, promote the in-depth integration of the energy industry with digital intelligence, and make greater contributions to ensuring national energy security. Robin Li said that the "intelligent emergence" and core capabilities of understanding, generation, logic, and memory displayed by large models have opened up a broader space for imagination for the combination of cutting-edge technology and oil and gas business. Always</p>
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<a href="https://www.php.cn/faq/757968.html" title="Advanced usage of reference parameters and pointer parameters in C++ functions" class="phphistorical_Version2_mids_img">
<img onerror="this.onerror=''; this.src='/static/imghw/default1.png'"
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<a href="https://www.php.cn/faq/757968.html" title="Advanced usage of reference parameters and pointer parameters in C++ functions" class="phphistorical_Version2_mids_title">Advanced usage of reference parameters and pointer parameters in C++ functions</a>
<span class="Articlelist_txts_time">Apr 21, 2024 am 09:39 AM</span>
<p class="Articlelist_txts_p">Reference parameters in C++ functions (essentially variable aliases, modifying the reference modifies the original variable) and pointer parameters (storing the memory address of the original variable, modifying the variable by dereferencing the pointer) have different usages when passing and modifying variables. Reference parameters are often used to modify original variables (especially large structures) to avoid copy overhead when passed to constructors or assignment operators. Pointer parameters are used to flexibly point to memory locations, implement dynamic data structures, or pass null pointers to represent optional parameters.</p>
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<a href="https://www.php.cn/faq/1784610.html" title="How to detect URL with regular expression in Golang?" class="phphistorical_Version2_mids_img">
<img onerror="this.onerror=''; this.src='/static/imghw/default1.png'"
src="/static/imghw/default1.png" class="lazy" data-src="https://img.php.cn/upload/article/000/000/164/171712275260421.jpg?x-oss-process=image/resize,m_fill,h_207,w_330" alt="How to detect URL with regular expression in Golang?" />
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<a href="https://www.php.cn/faq/1784610.html" title="How to detect URL with regular expression in Golang?" class="phphistorical_Version2_mids_title">How to detect URL with regular expression in Golang?</a>
<span class="Articlelist_txts_time">May 31, 2024 am 10:32 AM</span>
<p class="Articlelist_txts_p">The steps to detect URLs in Golang using regular expressions are as follows: Compile the regular expression pattern using regexp.MustCompile(pattern). Pattern needs to match protocol, hostname, port (optional), path (optional) and query parameters (optional). Use regexp.MatchString(pattern,url) to detect whether the URL matches the pattern.</p>
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