php expects parameter 1 to be resource, array given error_PHP Tutorial

If you are using a packaged class
for example
function fetch_array($query, $result_type = MYSQL_ASSOC) {
return mysql_fetch_array($query, $result_type);
}
[/ code]
This error will be reported
This is because the $query you pass is a Boolean value, and the parameters in mysql_fetch_array require resource types. This is because your program will determine that the parameters you pass are wrong. ,
We can

Copy code The code is as follows:

function fetch_array($query, $result_type = MYSQL_ASSOC) {
return @mysql_fetch_array($query, $result_type);
}

Use @ in front to suppress error prompts, or
try the interpretation statement to execute this statement,

Copy code The code is as follows:

if (this parameter)
{
Execute
}

http://www.bkjia.com/PHPjc/323052.htmlwww.bkjia.comtruehttp: //www.bkjia.com/PHPjc/323052.htmlTechArticleIf you are using a packaged class such as function fetch_array($query, $result_type = MYSQL_ASSOC) { return mysql_fetch_array ($query, $result_type); } [/code] will report this error...