Intercepting strings in php supports utf-8_PHP tutorial

WBOY
Release: 2016-07-21 15:57:41
Original
843 people have browsed it

Intercept string
$string="I turned one year older in April 2006!";
echo substr($string,1)."...";
//Intercept string
function SubstrGB($in,$num)
{
$pos=0;
$out="";
while($pos {
$c=substr($in,$pos,1);
if($c=="n") break;
if(ord($c) >128)
{
$out.=$c;
$pos++;
$c=substr($in,$pos,1);
$out.=$c ;
}
else
{
$out.=$c;
}
$pos++;
if($pos>=$num) break;
}
return $out;
}
echo SubstrGB($string,8);
?>
/***************************************************** ***********************
*             cut_string.php
*                                                                                          --------------
* Date : Jul 16, 2005
* Copyright : none
* Mail :
*
* Function: intercept Chinese characters .
*
*
****************************************** *************************************/
function cut_str($string, $sublen, $start = 0, $code = 'UTF-8')
{
if($code == 'UTF-8')
{
$pa = "/[x01-x7f]|[xc2-xdf][x80-xbf]|xe0[xa0-xbf][x80-xbf]|[xe1-xef][x80-xbf][x80-xbf]| xf0[x90-xbf][x80-xbf][x80-xbf]|[xf1-xf7][x80-xbf][x80-xbf][x80-xbf]/";
preg_match_all($pa, $string , $t_string);
if(count($t_string[0]) - $start > $sublen) return join('', array_slice($t_string[0], $start, $sublen)).". ..";
return join('', array_slice($t_string[0], $start, $sublen));
}
else
{
$start = $start* 2;
$sublen = $sublen*2;
$strlen = strlen($string);
$tmpstr = '';
for($i=0; $i<$strlen; $i++)
{
if($i>=$start && $i<($start+$sublen))
{
if(ord(substr($string, $i, 1) )>129) $tmpstr.= substr($string, $i, 2);
    else $tmpstr.= substr($string, $i, 1); substr($string, $i, 1))>129) $i++; return $tmpstr;
}
}
echo "
".cut_str($string,8,$start=0,$code='sdf');
?>




http://www.bkjia.com/PHPjc/317768.html

www.bkjia.com

truehttp: //www.bkjia.com/PHPjc/317768.htmlTechArticleIntercept string?php $string="In April 2006, I became one year older!"; echosubstr ($string,1)."..."; //Intercept string functionSubstrGB($in,$num) { $pos=0; $out=""; while($posstrlen($in...
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template