Detailed explanation of PHP function: parse_url()

WBOY
Release: 2016-07-25 08:46:40
Original
1268 people have browsed it
parse_url() function can parse a URL and return its component parts. It is used as follows:
array parse_url ( string url )
This function returns an associative array containing the various components of the existing URL. If one of these components is missing, no array entry will be created for this component. The components are:
  • scheme - like http
  • host
  • port
  • user
  • pass
  • path
  • query - after the question mark ?
  • fragment - after the hash symbol #
This function does not mean that the given URL is valid, it just separates the parts in the list above. parse_url() accepts incomplete URLs and tries to parse them correctly. This function has no effect on relative path URLs.
  1.                                                                                                                                                                                                                                                              Print_r($parts );
  2. ?>

  3. Copy code

The program running results are as follows:

Array ( [scheme] => http [host] => www.nowamagic.net [path] => /welcome/ )
< ;?php
  1.                                                                                     use using using  -                                                                      
  2. ?>

  3. Copy code



  4. Program output:

Array
( [scheme] => http
[host] => hostname
[user] => username
  1. [pass] = > password
  2. [path] => /path
  3. [query] => arg=value
  4. [fragment] => anchor
  5. )
  6. /path

  7. Copy code



  8. You can see that it is easy to decompose the various parts of a URL, and it is also easy to get the specified parts, such as:

echo parse_url($url, PHP_URL_PATH);
Copy code
    In the second parameter, set the following parameters: PHP_URL_SCHEME, PHP_URL_HOST, PHP_URL_PORT, PHP_URL_USER, PHP_URL_PASS, PHP_URL_PATH, PHP_URL_QUERY or PHP_URL_FRAGMENT


Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!