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PHP code example to list all files in a directory

Jul 25, 2016 am 08:58 AM

This article introduces an example code that uses PHP to list all files in a directory for your reference.

List all files in the directory, the code is as follows:

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<?php

$current_dir = 'E:/temp/';

$dir = opendir($current_dir);

echo "direcotry list:<ul>";

while(false !== ($file=readdir($dir))){

if($file != "." && $file != ".."){

echo "<li>$file</li>";

}

} //by bbs.it-home.org

echo "</ul>";

closedir($dir);

?>

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If the directory and the website are in the same partition, you can also use $current_dir='/temp/'; directly.

The above is an example under Windows. Let’s look at a PHP example under Linux that lists all files in a directory. as follows: 1. Get the files in the directory, excluding subdirectories.

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<?php

//获取某目录下所有文件、目录名(不包括子目录下文件、目录名)

    $handler = opendir($dir);

    while (($filename = readdir($handler)) !== false) {//务必使用!==,防止目录下出现类似文件名“0”等情况

        if ($filename != "." && $filename != "..") {

                $files[] = $filename ;

           }

       }

    }

    closedir($handler);

      

//打印所有文件名

foreach ($filens as $value) {

    echo $value."<br />";

}

?>

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2. Get all files in the directory, including subdirectories.

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<?php

function get_allfiles($path,&$files) {

    if(is_dir($path)){

        $dp = dir($path);

        while ($file = $dp ->read()){

            if($file !="." && $file !=".."){

                get_allfiles($path."/".$file, $files);

            }

        }

        $dp ->close();

    }

    if(is_file($path)){

        $files[] =  $path;

    }

} //edit bbs.it-home.org

    

function get_filenamesbydir($dir){

    $files array();

    get_allfiles($dir,$files);

    return $files;

}

    

$filenames = get_filenamesbydir("static/image/");

//打印所有文件名,包括路径

foreach ($filenames as $value) {

    echo $value."<br />";

}

?>

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