PHP query voting exercise (0508)-PHP Tutorial-php.cn

PHP query voting exercise (0508)

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Release： 2016-07-29 08:50:41

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Practice questions:

php 之查询投票练习（0508）

Solution:

Method 1:

1. Main voting page:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" c />
<title>投票</title>
<style>
#list
{
	width:400px;
	height:300px;}
#jieguo
{
	width:400px;
	height:300px;}
.x
{
	
	float:left;}

</style>
</head>

<body>

<form action="TouChuLi.php" method="post">
<?php
include ("DBDA.class.php");
$db=new DBDA();
//从调研题目表中找出题目代号和名称
$sql="select * from diaoyantimu limit 0,1";
$arr=$db->query($sql);
$tmmc=$arr[0][1];
$tmdh=$arr[0][0];
echo "<div><h2>{$tmmc}:</h2></div>";
//从调研选项表中输出选项内容：
$sqlxx="select * from diaoyanxuanxiang where timudaihao='{$tmdh}'";
$arrxx=$db->query($sqlxx);
echo "<div>";
foreach ($arrxx as $v)
{
	echo "<div><input type='checkbox' value='{$v[0]}' name='xx[]'>{$v[1]}</div><br />";
}

?>
<input type="submit" value="提交">
<input type="button" value="查看结果" >
<?php
//计算总人数：
$sqlzs="select sum(numbers) from diaoyanxuanxiang where timudaihao='{$tmdh}'";
$zrs=$db->query($sqlzs);

foreach ($arrxx as $v)
{
	
	$name=$v[1];
	$number=$v[2];
	if($zrs[0][0]==0)
     {
         $bfb = 0;
     }
     else
     {
          $bfb = ($number/$zrs[0][0])*100;
     }
	$bfb=round($bfb,2);	
	echo "<div>
		<span>{$name} </span>
		<div >
		<div> </div>
		</div>
		<span>{$number} </span>
		<span>{$bfb}% </span>
		</div>
		<br />
		";	
}
?>
<input type="button" value="返回" ><div class="code" style="position:relative; padding:0px; margin:0px;"><pre class="brush:php;toolbar:false"><?php
$arr=$_POST["xx"];
include ("../DBDA.class.php");
$db=new DBDA();


foreach($arr as $v)
{
	$sql = "update diaoyanxuanxiang set numbers = numbers+1 where ids = '{$v}'";
	$db->Query($sql,1);//1代表$sql的类型
}
header ("location:TouPiao.php");
?>

Copy after login

<?php //执行一个sql语句，返回相应的结果 class DBDA { public $host="localhost";//数据库服务器地址 public $uid="root";//数据库用户名 public $password="";//数据库密码 //执行SQL语句的方法 //参数里面：$sql代表要执行的sql语句；$type是sql语句的类型，0代表查询，1代表其他(增删改)；$db代表要操作的数据库 function Query($sql,$type=0,$db="mydb") { //造连接对象 $dbc MySQLi($this->host,$this->uid,$this->password,$db); //判断连接是否出错 !mysqli_connect_error() or die("连接失败！"); //执行sql语句 $result=$dbconnect->query($sql); //判断SQL语句类型 if($type==0) { //如果是查询语句返回结果集的二维数组 return $result->fetch_all(); } else { //如果是其他语句，返回true或false return $result; } } }

<html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" c /> <title>投票</title> <style> .x { float:left;} </style> </head> <body> <form action="TouChuLi.php" method="post"> <?php include ("../DBDA.class.php"); $db=new DBDA(); //从调研题目表中找出题目代号和名称 $sql="select * from diaoyantimu limit 0,1"; $arr=$db->query($sql); $tmmc=$arr[0][1]; $tmdh=$arr[0][0]; echo "<div><h2>{$tmmc}:</h2></div>"; //从调研选项表中输出选项内容： $sqlxx="select * from diaoyanxuanxiang where timudaihao='{$tmdh}'"; $arrxx=$db->query($sqlxx); echo "<div>"; foreach ($arrxx as $v) { echo "<div><input type='checkbox' value='{$v[0]}' name='xx[]'>{$v[1]}</div><br />"; } ?> <input type="submit" value="提交"> <a href="ChaKan.php"><input type="button" value="查看结果" ></a> </form> </body> </html>

<?php $arr=$_POST["xx"]; include ("../DBDA.class.php"); $db=new DBDA(); foreach($arr as $v) { $sql = "update diaoyanxuanxiang set numbers = numbers+1 where ids = '{$v}'"; $db->Query($sql,1);//1代表$sql的类型 } header ("location:TouPiao.php"); ?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" c /> <title>查看结果</title> <style> .x { float:left;} </style> </head> <body> <?php include ("../DBDA.class.php"); $db=new DBDA(); //从调研题目表中找出题目代号和名称 $sql="select * from diaoyantimu limit 0,1"; $arr=$db->query($sql); $tmmc=$arr[0][1]; echo "<div><h2>{$tmmc}:</h2></div>"; //从调研选项表中输出选项内容： $sqlxx="select * from diaoyanxuanxiang where timudaihao='{$arr[0][0]}'"; $arrxx=$db->query($sqlxx); //计算总人数： $sqlzs="select sum(numbers) from diaoyanxuanxiang where timudaihao='{$arr[0][0]}'"; $zrs=$db->query($sqlzs); foreach ($arrxx as $v) { $name=$v[1];//调研项目名称 $number=$v[2];//选择该项的人数 //判断总人数是否为0 if($zrs[0][0]==0) { $bfb = 0; } else { $bfb = ($number/$zrs[0][0])*100;//求百分比 } $bfb=round($bfb,2); //取小数点后两位 echo "<div> <span>{$name} </span> <div > <div> </div> </div> <span>{$number} </span> <span>{$bfb}%</span><br /> </div><br />"; } ?> <br /> <a href="TouPiao.php"><input type="button" value="返回"></a> </body> </html>

The above introduces the PHP query voting exercise (0508), including PHP and exercise content. I hope it will be helpful to friends who are interested in PHP tutorials.