ajax cross-domain prompt Reload the page to get the source code

ajaxCode:

var mobile = document.myform.b1.value;
var email = document.myform.b2.value;
var username = document.myform.b3.value + document.myform.b4.value;
var count = 10;
var ojj;
$.<strong>ajax</strong>({
	type:'get',
	url:'http://a.com/app.php',
	data:{username:username,email:email,mobile:mobile},
	cache: false,
	dataType:'jsonp',
	jsonp:'callback',
	jsonpCallback:"success_jsonpCallback",
	success:function(e){		
		if(e=='reg_ok'){
			$("#reg_fail").addClass('LDisplayNone');
			$("#reg_ok").removeClass('LDisplayNone');
			$("#popup").show().css("height",$(window).height());
			count--;
			if(count <= 0){
				closePopup();
				return;
			}
			document.getElementById('timeshow').innerHTML = count;
			ojj=setTimeout(function(){Prompt()},1000);		
		}else{
			$("#reg_ok").addClass('LDisplayNone');
			$("#reg_fail").removeClass('LDisplayNone');
			$("#popup").show().css("height",$(window).height());
			count--;
			if(count <= 0){
				closePopup();
				return;
			}
			document.getElementById('timeshow').innerHTML = count;
			ojj=setTimeout(function(){Prompt()},1000);
		}
	},
	error : function(e) {    
        //console.log(e);  //有值
    }
});

app.php 文件

header("Access-Control-Allow-Origin: *");//First Cross-domain access is allowed. If it is *, it means that all addresses can be accessed. If it can only be accessed by a certain address, write the address directly and write the address starting with http.

json_encode($str)

The above introduces the ajax cross-domain prompt. Reload the page to obtain the source code, including ajax content. I hope it will be helpful to friends who are interested in PHP tutorials.