There are two select query results, one of which is content (text) and the other is a swear word. How to count the number of times content appears in a swear word.

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Release: 2016-08-04 09:20:09
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I can’t think of a perfect solution, it’s still rubbish after all.

I thought of an ugly method, just take a look:

$str = "1111111111111112b22222222caonima22222222";
$words = ['2b','caonima'];
$res = [];
foreach($words as $word){
    $res[$word] = count(explode($word, $str))-1;
}
return $res;
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If you only count the number of swear words, and do not require the number of each swear word, I have previously written a function that cuts strings based on multiple keys

$str = "1111111111111112b22222222caonima22222222";
$words = ['2b','caonima'];
function many_explode($cutKey,$string){
    $return=[];
    $key=0;
    for($i=0;$i<strlen($string);$i++){
        if(in_array($string[$i], $cutKey)){
            $key++; //当前字符在 cutKey 中,跳过,并另起一行
        }else{
            $return[$key]=isset($return[$key])?$return[$key].$string[$i]:$string[$i];
        }
    }
    return $return;
}
return count(many_explode($words, $str)) -1;
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Change the soup without changing the medicine

1. Create a table with all the keywords of swear words.

2. Use the content context as a full-text index.

3. Use the function that comes with mysql to search locate, or you can use like.

$arr = array(&#39;2b&#39;, &#39;fuck&#39;);
$con = array(
        array(
            &#39;content&#39;=>&#39;asdfasdf2bsdfasdf2dfasdfuck&#39;
            ),
        array(
            &#39;content&#39;=>&#39;asdfasdf2asdfasdf2dfasdfuck&#39;
            ),
        array(
            &#39;content&#39;=>&#39;asdfasdfuckbsdfasdf2dfasdfuck&#39;
            ),
    );
foreach($con as $ck => $cv) {
    foreach ($arr as $av) {
        if (($pos = strpos($cv[&#39;content&#39;], $av)) !== false) {
            $cv[&#39;checkCount&#39;][$av] = recursionSearch($cv[&#39;content&#39;], $av, $pos, 1);
        }
    }
    $con[$ck] = $cv;
}
print_r($con); //
function recursionSearch($haystack, $needle, $offset=0, $res=0 ) {
    $offset += strlen($needle); 
    if (($pos = strpos($haystack, $needle, $offset)) === false) {
        return $res;
    } else {
        return recursionSearch($haystack, $needle, $pos, $res+1 );
    }
}
// 打印结果
/**
Array
(
    [0] => Array
        (
            [content] => asdfasdf2bsdfasdf2dfasdfuck
            [checkCount] => Array
                (
                    [2b] => 1
                    [fuck] => 1
                )
        )
    [1] => Array
        (
            [content] => asdfasdf2asdfasdf2dfasdfuck
            [checkCount] => Array
                (
                    [fuck] => 1
                )
        )
    [2] => Array
        (
            [content] => asdfasdfuckbsdfasdf2dfasdfuck
            [checkCount] => Array
                (
                    [fuck] => 2
                )
        )
)
**/
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Thank you for your answers. I have learned a variety of writing methods. I used the first one provided by qvga, and then added array_sum to count the total. Thank you ^_^

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