php splice pictures and keep the previous color of the previous picture

I have a function to splice two pictures. Here is my code

<code>    $im     = imagecreatefrompng("images/err.png");
    $stamp = imagecreatefrompng('images/default.png');
    $test = imagecreate(imagesx($stamp)+imagesx($im),imagesy($im));
    $orange = imagecolorallocate($test, 255, 255, 255);
   // image
    imagecopy($test, $stamp, 0, 0, 0, 0, imagesx($stamp), imagesy($stamp));
    imagecopy($test, $im, imagesx($stamp), 0, 10, 0, imagesx($im), imagesy($im));
    header("Content-type: image/png");
    imagepng($test);
    最终的结果是 第二个拼接的图片的颜色都会跟着第一个变化 因为传不上图片只能文字描述下面假如AB是拼接好的图片 有A和B拼接成 B的颜色本来是红色但是拼接完成之后B的颜色会变成A的颜色
</code>

AB

Reply content:

I have a function to splice two pictures. Here is my code

<code>    $im     = imagecreatefrompng("images/err.png");
    $stamp = imagecreatefrompng('images/default.png');
    $test = imagecreate(imagesx($stamp)+imagesx($im),imagesy($im));
    $orange = imagecolorallocate($test, 255, 255, 255);
   // image
    imagecopy($test, $stamp, 0, 0, 0, 0, imagesx($stamp), imagesy($stamp));
    imagecopy($test, $im, imagesx($stamp), 0, 10, 0, imagesx($im), imagesy($im));
    header("Content-type: image/png");
    imagepng($test);
    最终的结果是 第二个拼接的图片的颜色都会跟着第一个变化 因为传不上图片只能文字描述下面假如AB是拼接好的图片 有A和B拼接成 B的颜色本来是红色但是拼接完成之后B的颜色会变成A的颜色
</code>

AB

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