获取URL文件名后缀_php实例

WBOY
Release: 2016-05-17 08:54:30
Original
1133 people have browsed it

尽可能高效的,从一个标准 url 里取出文件的扩展名,再把代码扩展一下就可以得到其它的数据了,比如:目录路径,原理就是使用PHP的explode函数分隔字符串。
例如: http://www.abc.com/abc/de/fg.php?id=1 需要取出 php 或 .php
很简单,直接看代码。

复制代码 代码如下:

$url = "http://www.abc.com/abc/de/fg.php?id=1";

//这个是自己写的
function getUrl($url) {
    $date = explode('?', $url);
    $date = basename($date[0]);
    $date = explode('.', $date);
    return $date[1];
}

var_dump(getUrl($url));

//下面两个是网上弄的
function getExt($url){
   $arr = parse_url($url);

   $file = basename($arr['path']);
   $ext = explode(".",$file);
   return $ext[1];
}

var_dump(getExt($url));

 

function getName($url) {

   $w_param = pathinfo($url);

   $str = $w_param['extension'];

   list($type, $vars) = explode('?',$str);

   return $type;

}
echo 'start3'.date("Y-m-d H:i:s");
?>

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