The rules are as follows:
Password format: 6-16 digit alphanumeric combination
Does not contain special characters.
Must contain 3 characters including numbers, uppercase letters, and lowercase letters, and are case-sensitive.
Consecutive 3-digit or more numbers cannot be consecutive (such as 123, 876)
Consecutive 3-digit or more letters cannot be consecutive (such as abc, cba, aaa, 111, AAA)
<code>echo !preg_match('/\d{3,}|[a-zA-Z]{3,}/', $password); echo preg_match('/\d+/', $password); echo preg_match('/[a-z]+/', $password); echo preg_match('/[A-Z]+/', $password); echo preg_match('/^([a-zA-Z0-9]){6,16}$/', $password); </code>
The above are the requirements and the solutions I came up with
But I always want to match it in a more concise way. I hope someone can have a better idea.
Another question: Why are regular expressions inefficient?
Because it is too complicated and inefficient to use regular expressions to judge consecutive numbers and letters, so I use logical code judgment. Here is the code I wrote in PHP. The initial test on php5.5.12 was successful.
<code>/** * 密码格式:6-16位数字字母组合 * 不包含特殊字符。 * 必须同时包含数字、大写字母,小写字母3种字符,区分大小写。 * 连续3位及以上数字不能连续(例如123、876) * 连续3位及以上的字母不能连续(例如abc、cba) * @param string $password * @return boolean 是否匹配 */ function CheckPassword($password){ if (strlen($password) > 16 || strlen($password) < 6) { return false; } // ASCII code vallue $upperLetter = range(65, 90); $lowerLetter = range(97, 122); $number = range(48, 57); $includeNumber = false; $includeUpperLetter = false; $includeLowerLetter = false; $continuousCharNum = 0; for ($i=0; !empty($password[$i]); $i++) { // 特殊字符 if (!in_array(ord($password[$i]), array_merge($upperLetter, $lowerLetter, $number))) { return false; } // 大写字母 if (!$includeUpperLetter && in_array(ord($password[$i]), $upperLetter)) { $includeUpperLetter = true; } // 数字 if (!$includeNumber && in_array(ord($password[$i]), $number)) { $includeNumber = true; } // 小写字母 if (!$includeLowerLetter && in_array(ord($password[$i]), $lowerLetter)) { $includeLowerLetter = true; } if ($i != 0 && !empty($password[$i+1]) && abs(ord($password[$i]) - ord($password[$i-1])) <= 1 && ord($password[$i]) - ord($password[$i-1]) == ord($password[$i+1]) - ord($password[$i])) { return false; } } if ($includeLowerLetter && $includeNumber && $includeUpperLetter) { return true; } else { return false; } }</code>