Home > php教程 > PHP源码 > body text

The simplest example of php+jquery+ajax+json

大家讲道理
Release: 2016-11-08 13:54:15
Original
1090 people have browsed it

html页面:

<html>
 <head>
 <meta http-equiv="content-type" content="text/html;charset=utf-8" />
 <script type="text/javascript" src="jquery-1.8.2.min.js"></script>
 <script type="text/javascript">
  $(function(){
       $("#send").click(function(){
        var cont = $("input").serialize();
        $.ajax({
             url:&#39;ab.php&#39;,
             type:&#39;post&#39;,
             dataType:&#39;json&#39;,
             data:cont,
             success:function(data){
              var str = data.username + data.age + data.job;
              $("#result").html(str);
         }
    });
   });  
  });
 </script>
 </head>
 <body>
 <div id="result">一会看显示结果</div>
 <form id="my" action="" method="post">
            <p><span>姓名:</span> <input type="text" name="username" /></p>
           <p><span>年龄:</span><input type="text" name="age" /></p>
           <p><span>工作:</span><input type="text" name="job" /></p>
 </form>
 <button id="send">提交</button>
 </body>
 </html>
Copy after login

/*******************************************/

php页面:

<?php
 header("Content-type:text/html;charset=utf-8");
         $username = $_POST[&#39;username&#39;];
         $age = $_POST[&#39;age&#39;];
         $job = $_POST[&#39;job&#39;];
         $json_arr = array("username"=>$username,"age"=>$age,"job"=>$job);
         $json_obj = json_encode($json_arr);
         echo $json_obj;
 ?>
Copy after login

使用post方式

<script type="text/javascript">
  $(function(){
   $("#send").click(function(){
       var cont = {username:$("input")[0].value,age:$("input")[1].value,job:$("input")[2].value};
       var url = &#39;ab.php&#39;;
       $.post(url,cont,function(data){
        var res = eval("(" + data + ")");//转为Object对象
       var str = res.username + res.age + res.job;
     $("#result").html(str);
    });
   });  
  });
 </script>
Copy after login

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Recommendations
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!