php empty()与isset()区别的详细介绍_php技巧
在使用 php 编写页面程序时,我经常使用变量处理函数判断 php 页面尾部参数的某个变量值是否为空,开始的时候我习惯了使用 empty() 函数,却发现了一些问题,因此改用 isset() 函数,问题不再。
顾名思义,empty() 判断一个变量是否为“空”,isset() 判断一个变量是否已经设置。正是这种所谓的“顾名思义”,令我开始时走了些弯路:当一个变量值等于0时,empty()也会成立(True),因而会发生 一些意外。原来,empty() 和 isset() 虽然都是变量处理函数,它们都用来判断变量是否已经配置,它们却是有一定的区别:empty还会检测变量是否为空、为零。当一个变量值为0,empty() 认为这个变量同等于空,即相当于没有设置。
比如检测 $id 变量,当 $id=0 时,用empty() 和 isset() 来检测变量 $id 是否已经配置,两都将返回不同的值—— empty() 认为没有配置,isset() 能够取得 $id 的值:
$id=0;
empty($id)?print "It's empty .":print "It's $id .";
//结果:It's empty .
print "
";
!isset($id)?print "It's empty .":print "It's $id .";
//结果:It's 0 .
这意味着,我们在使用变量处理函数时,当该变量可能出现0的值,使用 empty() 要小心,这个时候用 isset 取代它更明智一些。
当一个php页面的 URL 尾部参数出现 id=0 时(比如:test.php?id=0),试比较:
if(empty($id)) $id=1; - 若 id=0 ,id 也会为1
if(!isset($id)) $id=1; - 若 id=0 ,id 不会为1
可分开运行以下代码检测上述推断:
if(empty($id)) $id=1;
print $id; // 得到 1
if(!isset($id)) $id=1;
print $id; //得到 0

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