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javascript - Ajax error in obtaining json data from the server, JSON.parse(xhr.responseText),,,?
javascript - Ajax error in obtaining json data from the server, JSON.parse(xhr.responseText),,,?
html page:
<code><!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>无标题文档</title>
</head>
<body>
<form action="reg.php" method="post" >
用户名 : <input id="input1" type="text" name="username">
<input type="submit" value="注册">
</form>
<div id="div1"></div>
<script>
var oInput = document.getElementById('input1');
var oDiv = document.getElementById('div1');
oInput.onblur = function(){
var xhr = new XMLHttpRequest();
xhr.open('GET','ajax.php?username='+encodeURIComponent(this.value),true);
xhr.onreadystatechange = function(){
if(xhr.readyState == 4){
if(xhr.status == 200){
var obj = JSON.parse(xhr.responseText);
if(obj.code){
oDiv.innerHTML = obj.message;
}
else{
oDiv.innerHTML = obj.message;
}
}
}
};
xhr.send(null);
};
</script>
</body>
</html></code>php page:
<code><?php
header('Content-type:text/html;charset=utf-8');
$conn = mysqli_connect('127.0.0.1', 'root', '5221107073', 'linshi');
$name = $_GET['username'];
$sql = "SELECT * FROM shi where name='$name'";
$res = mysqli_query($conn, $sql);
if($res && mysqli_num_rows($res)){
echo "{'code':'0','message':'该名字有人注册'}";
}else{
echo "{'code':'1','message':'ok'}";
}
?></code>It means that the json data cannot be obtained from the server, and the error is as follows:
<code>SyntaxError: JSON.parse: unexpected character at line 1 column 1 of the JSON data</code>
Solve
Reply content:
html page:
<code><!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>无标题文档</title>
</head>
<body>
<form action="reg.php" method="post" >
用户名 : <input id="input1" type="text" name="username">
<input type="submit" value="注册">
</form>
<div id="div1"></div>
<script>
var oInput = document.getElementById('input1');
var oDiv = document.getElementById('div1');
oInput.onblur = function(){
var xhr = new XMLHttpRequest();
xhr.open('GET','ajax.php?username='+encodeURIComponent(this.value),true);
xhr.onreadystatechange = function(){
if(xhr.readyState == 4){
if(xhr.status == 200){
var obj = JSON.parse(xhr.responseText);
if(obj.code){
oDiv.innerHTML = obj.message;
}
else{
oDiv.innerHTML = obj.message;
}
}
}
};
xhr.send(null);
};
</script>
</body>
</html></code>php page:
<code><?php
header('Content-type:text/html;charset=utf-8');
$conn = mysqli_connect('127.0.0.1', 'root', '5221107073', 'linshi');
$name = $_GET['username'];
$sql = "SELECT * FROM shi where name='$name'";
$res = mysqli_query($conn, $sql);
if($res && mysqli_num_rows($res)){
echo "{'code':'0','message':'该名字有人注册'}";
}else{
echo "{'code':'1','message':'ok'}";
}
?></code>It means that the json data cannot be obtained from the server, and the error is as follows:
<code>SyntaxError: JSON.parse: unexpected character at line 1 column 1 of the JSON data</code>
Solve
The header setting is wrong. This setting outputs html in utf-8 format.
Use
<code>header('Content-type: application/json');</code>In this way, the echo data is in json format.
It is recommended to save the content to be output into an array and use it where it is to be output.
<code>echo json_encode($array);</code>
I haven’t tried it. Try not to write it directly like this. Instead, write it differently, define an array, and then json_encode().
The format returned by the backend is wrong
echo '{"code":"0","message":"该名字有人注册"}'
The format is wrong, there are double quotes in json.
This kind
echo '{"code":"0","message":"该名字有人注册"}'
I output the results obtained from the server on the front page `if(xhr.readyState == 4){
<code> if(xhr.status == 200){
console.log(xhr.responseText);
console.log(JSON.parse(xhr.responseText));
}
}`</code>This is what you see on the console (that is, is there a problem with obtaining xhr.responseText?): 
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