wx.getLocation({
<code> type: 'wgs84', // 默认为wgs84的gps坐标,如果要返回直接给openLocation用的火星坐标,可传入'gcj02' success: function (res) { var latitude = res.latitude; // 纬度,浮点数,范围为90 ~ -90 var longitude = res.longitude; // 经度,浮点数,范围为180 ~ -180。 var speed = res.speed; // 速度,以米/每秒计 var accuracy = res.accuracy; // 位置精度 $.ajax({ url:"{:U('home/Share/index')}", data:{latitude:latitude,longitude:longitude}, type:"POST", dataType:"json", success:function(){ } }) }, })</code>
When using ajax to transfer values to the background controller, var_dump($_POST) is a null value. What’s going on?
wx.getLocation({
<code> type: 'wgs84', // 默认为wgs84的gps坐标,如果要返回直接给openLocation用的火星坐标,可传入'gcj02' success: function (res) { var latitude = res.latitude; // 纬度,浮点数,范围为90 ~ -90 var longitude = res.longitude; // 经度,浮点数,范围为180 ~ -180。 var speed = res.speed; // 速度,以米/每秒计 var accuracy = res.accuracy; // 位置精度 $.ajax({ url:"{:U('home/Share/index')}", data:{latitude:latitude,longitude:longitude}, type:"POST", dataType:"json", success:function(){ } }) }, })</code>
When using ajax to transfer values to the background controller, var_dump($_POST) is a null value. What’s going on?
The writing is correct. As for why you can’t get it, you need to debug your code yourself.
Meat testing method:
Output the received data directly, and then accept the returned object in success
.
<code>后台输出: echo json_encode($_POST);exit(); 前台输出: success:function(msg){ console.log(msg); }</code>
ajax is an asynchronous request and cannot be output directly in the controller