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How does Java read XML files? Specific implementation

高洛峰
Release: 2017-01-11 12:36:00
Original
2431 people have browsed it

Today’s CSDN FAQ will explain how to read the content of XML files in Java.

Just go to the code, the comments are very clear!

import java.io.*;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
public class XMLReaderTest {
 public static void main(String args[]) {
  Element element = null;
  // 可以使用绝对路劲
  File f = new File("test.xml");
  // documentBuilder为抽象不能直接实例化(将XML文件转换为DOM文件)
  DocumentBuilder db = null;
  DocumentBuilderFactory dbf = null;
  try {
   // 返回documentBuilderFactory对象
   dbf = DocumentBuilderFactory.newInstance();
   // 返回db对象用documentBuilderFatory对象获得返回documentBuildr对象
   db = dbf.newDocumentBuilder();
   // 得到一个DOM并返回给document对象
   Document dt = db.parse(f);
   // 得到一个elment根元素
   element = dt.getDocumentElement();
   // 获得根节点
   System.out.println("根元素:" + element.getNodeName());
   // 获得根元素下的子节点
   NodeList childNodes = element.getChildNodes();
   // 遍历这些子节点
   for (int i = 0; i < childNodes.getLength(); i++) {
    // 获得每个对应位置i的结点
    Node node1 = childNodes.item(i);
    if ("Account".equals(node1.getNodeName())) {
     // 如果节点的名称为"Account",则输出Account元素属性type
     System.out.println("\r\n找到一篇账号. 所属区域: " + node1.getAttributes().getNamedItem("type").getNodeValue() + ". ");
     // 获得<Accounts>下的节点
     NodeList nodeDetail = node1.getChildNodes();
     // 遍历<Accounts>下的节点
     for (int j = 0; j < nodeDetail.getLength(); j++) {
      // 获得<Accounts>元素每一个节点
      Node detail = nodeDetail.item(j);
      if ("code".equals(detail.getNodeName())) // 输出code
       System.out.println("卡号: " + detail.getTextContent());
      else if ("pass".equals(detail.getNodeName())) // 输出pass
       System.out.println("密码: " + detail.getTextContent());
      else if ("name".equals(detail.getNodeName())) // 输出name
       System.out.println("姓名: " + detail.getTextContent());
      else if ("money".equals(detail.getNodeName())) // 输出money
       System.out.println("余额: " + detail.getTextContent());
     }
    }
   }
  }
  catch (Exception e) {
   e.printStackTrace();
  }
 }
}
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Then the XML file (test.xml) we test should be placed in the root directory of the project project. Its content is:

<?xml version="1.0" encoding="gbk"?>
<Accounts>
 <Account type="type1">
  <code>100001</code>
  <pass>123</pass>
  <name>李四</name>
  <money>1000000.00</money>
 </Account>
 <Account type="type2">
  <code>100002</code>
  <pass>123</pass>
  <name>张三</name>
  <money>1000.00</money>
 </Account>
</Accounts>
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Run the code directly and output:

Root element: Accounts

Found an account number. Area: type1.
Card number: 100001
Password: 123
Name: Li Si
Balance: 1000000.00

Find an account. Area: type2.
Card number: 100002
Password: 123
Name: Zhang San
Balance: 1000.00

More How to read XML in Java Please pay attention to the PHP Chinese website for articles related to the specific implementation of the file!

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