The example of this article describes the method of intercepting pairs of brackets using Python regular expressions. Share it with everyone for your reference, as follows:
strs = '1(2(3(4(5(67)6)7)8)9)0' reg1 = re.compile('([()])∗') #一对括号 reg2 = re.compile('([()]|\([()]∗)*\)') #两对括号 reg3 = re.compile('([()]|\([()]∗|([()]|\([()]∗)*\))*\)') #三层
Function
#匹配成对括号正则表达式 def getReg(self, count, bracket = '()'): leftBracket = bracket[0] rightBracket = bracket[1] count -= 1 regBasic = leftBracket + '(?:[^' + leftBracket + rightBracket + '])*' + rightBracket if count < 0: regBasic = '' if count > 0: for i in xrange(count): tempNum = regBasic.rfind('*') - 1 regBasic = regBasic[:tempNum] + "|" + regBasic + regBasic[tempNum:] return regBasic
I hope this article will be helpful to everyone in Python programming.
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