Home > Web Front-end > JS Tutorial > body text

JavaScript password strength judgment code

高洛峰
Release: 2017-01-16 09:16:54
Original
1281 people have browsed it

<script type="text/javascript"> 
//CharMode函数 
//测试某个字符是属于哪一类. 
function CharMode(iN){ 
if (iN>=48 && iN <=57) //数字 
return 1; 
if (iN>=65 && iN <=90) //大写字母 
return 2; 
if (iN>=97 && iN <=122) //小写 
return 4; 
else 
return 8; //特殊字符 
} 

//bitTotal函数 
//计算出当前密码当中一共有多少种模式 
function bitTotal(num){ 
modes=0; 
for (i=0;i<4;i++){ 
if (num & 1) modes++; 
num>>>=1; 
} 
return modes; 
} 

//checkStrong函数 
//返回密码的强度级别 

function checkStrong(sPW){ 
if (sPW.length<=4) 
return 0; //密码太短 
Modes=0; 
for (i=0;i<sPW.length;i++){ 
//测试每一个字符的类别并统计一共有多少种模式. 
Modes|=CharMode(sPW.charCodeAt(i)); 
} 

return bitTotal(Modes); 

} 

//pwStrength函数 
//当用户放开键盘或密码输入框失去焦点时,根据不同的级别显示不同的颜色 

function pwStrength(pwd){ 
O_color="#eeeeee"; 
L_color="#FF0000"; 
M_color="#FF9900"; 
H_color="#33CC00"; 
if (pwd==null||pwd==&#39;&#39;){ 
Lcolor=Mcolor=Hcolor=O_color; 
} 
else{ 
S_level=checkStrong(pwd); 
switch(S_level) { 
case 0: 
Lcolor=Mcolor=Hcolor=O_color; 
case 1: 
Lcolor=L_color; 
Mcolor=Hcolor=O_color; 
break; 
case 2: 
Lcolor=Mcolor=M_color; 
Hcolor=O_color; 
break; 
default: 
Lcolor=Mcolor=Hcolor=H_color; 
} 
} 

document.getElementById("strength_L").style.background=Lcolor; 
document.getElementById("strength_M").style.background=Mcolor; 
document.getElementById("strength_H").style.background=Hcolor; 
return; 
} 
</script> 


<form name=form1 action="" > 
输入密码:<input type=password size=10 onKeyUp=pwStrength(this.value) onBlur=pwStrength(this.value)> 
<br>密码强度: 
<table width="217" border="1" cellspacing="0" cellpadding="1" bordercolor="#cccccc" height="23" style=&#39;display:inline&#39;> 
<tr align="center" bgcolor="#eeeeee"> 
<td width="33%" id="strength_L">弱</td> 
<td width="33%" id="strength_M">中</td> 
<td width="33%" id="strength_H">强</td> 
</tr> 
</table> 
</form>
Copy after login

For more articles related to JavaScript password strength judgment code, please pay attention to the PHP Chinese website!

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!