The examples in this article summarize the usage of generics in Java. Share it with everyone for your reference. The details are as follows:
1 Basic use
public interface List<E> { void add(E); Iterator<E> iterator(); }
2 Generics and subclasses
Child is a subclass of Parent, but List
So: List
List<String> ls = new ArrayList<String>(); //1 List<Object> lo = ls; //2 lo.add(new Object()); // 3 String s = ls.get(0); // 4,将object转换为string将失败。
3 wildcards
Because of reason 2, the following implementation cannot be used to unify the output of the collection.
void printCollection(Collection<Object> c) { for (Object o: c) { // do something } }
Therefore, the wildcard ? is needed:
void printCollection(Collection<?> c) { for (Object o: c) { // 1 // do something } } // ok
The ? here indicates that the type is unknown, but any object is Object, so 1 in the above example is correct. But the following example is wrong:
void add(Collection<? extends MyClass> c) { c.add(new MyClass()); // wrong } // ok
The reason is also very clear, ? extends MyClass indicates that the type is a subclass of MyClass, but the specific type is not known
4. Generic method
The above example can be implemented as:
<T> add(Collection<T> c, T t) { c.add(t); }
The compiler will help with type conversion while ensuring semantics.
5. Comparison of generic runtime
List<String> l1 = new ArrayList<String>(); List<Integer> l2 = new ArrayList<Integer>(); System.out.println(l1.getClass() == l2.getClass()); // true
Because the runtime of generic classes is the same.
6 Generic array (may lead to type insecurity)
List<String>[] lsa = new ArrayList<String>[10]; // error
If possible, may lead to type insecurity. Such as:
Object o = lsa; Object []oa = (Object[])o; List<Integer> li = new ArrayList<Integer>(); li.add(new Integer(3)); oa[1] = li; String s = lsa[1].get(0); // runtime error
I hope this article will be helpful to everyone’s java programming.
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