A brief discussion on the small deviation problem of Java double multiplication results

Look at the running result of the following piece of code:

public class TestDouble {
 
public static void main(String[] args) {
 
double d =538.8;
 
System.out.println(d*100);
 
}

The output result is surprisingly not 53880, but 53879.99999999999

Solution 1 :

538.8*100 Replace with *10*10 to get the result we want

538.8*10000 Replace with 100*100.

Solution 2:

public class TestDouble {
  public static void main(String[] args) {
   double d =538.8;  
   BigDecimal a1 = new BigDecimal(Double.toString(d));
   BigDecimal b1 = new BigDecimal(Double.toString(100)); 
   BigDecimal result = a1.multiply(b1);// 相乘结果
   System.out.println(result);
   BigDecimal one = new BigDecimal("1");
   double a = result.divide(one,2,BigDecimal.ROUND_HALF_UP).doubleValue();//保留1位数
   System.out.println(a);
  }
}

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