Java Example - Find specified element in array

The following example demonstrates how to use the contains () method to find the specified element in the array:

/*
 author by w3cschool.cc
 文件名：Main.java
 */import java.util.ArrayList;public class Main {
   public static void main(String[] args)  {
      ArrayList objArray = new ArrayList();
      ArrayList objArray2 = new ArrayList();
      objArray2.add(0,"common1");
      objArray2.add(1,"common2");
      objArray2.add(2,"notcommon");
      objArray2.add(3,"notcommon1");
      objArray.add(0,"common1");
      objArray.add(1,"common2");
      System.out.println("objArray 的数组元素："+objArray);
      System.out.println("objArray2 的数组元素："+objArray2);
      System.out.println("objArray 是否包含字符串common2? ： "
      +objArray.contains("common1"));
      System.out.println("objArray2 是否包含数组 objArray? ："
      +objArray2.contains(objArray) );
   }}

The output result of running the above code is:

objArray 的数组元素：[common1, common2]
objArray2 的数组元素：[common1, common2, notcommon, notcommon1]
objArray 是否包含字符串common2? ： true
objArray2 是否包含数组 objArray? ：false

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