JavaScript finds the maximum and minimum value in an array

The minimum value algorithm is as follows:

1. Assign the first element in the array to a variable and use this variable as the minimum value;

2. Start traversing the array, starting from the second element and comparing it with the first element in sequence;

3. If the current element is less than the current minimum value, replace the current Assign the element value to the minimum value;

4. Move to the next element and continue the third step;

5. When the array element traversal ends , this variable stores the minimum value;

The code is as follows:

// 查找数组中最小值
function arrayMin(arrs){
    var min = arrs[0];
    for(var i = 1, ilen = arrs.length; i < ilen; i+=1) {
        if(arrs[i] < min) {
            min = arrs[i];
        }
    }
    return min;
}
// 代码测试
var rets = [2,4,5,6,7,9,10,15];
console.log(arrayMin(rets));//2

The above compares the values ​​​​in the array, if the number in the array is a string If so, you need to convert the string into a number first and then compare it, because the string comparison is not the value, but the ASCII code. For example, the ASCLL code of 2 will be greater than the ASCII code of 15, because the first number of the code of 15 is The ASCII encoding of 1 and 2 is definitely greater than 1;

The algorithm for finding the maximum value is similar to the above:

1. Assign the first element in the array to a variable, Use this variable as the maximum value;

2. Start traversing the array, starting from the second element and comparing it with the first element in sequence;

3. If the current element is greater than the current maximum value, assign the current element value to the maximum value;

4. Move to the next element and continue the third step;

5. When the array element traversal ends, this variable stores the minimum value;

The code is as follows:

// 在数组中查找最大值
function arrayMax(arrs) {
    var max = arrs[0];
    for(var i = 1,ilen = arrs.length; i < ilen; i++) {
        if(arrs[i] > max) {
            max = arrs[i];
        }
    }
    return max;
}
// 代码测试
var rets = [2,4,5,6,7,9,10,15];
console.log(arrayMax(rets));//15

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