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Simple methods and techniques for php to obtain all file names in a directory and determine files and directories

黄舟
Release: 2023-03-06 11:40:02
Original
4132 people have browsed it

The following editor will bring you a simple method of getting all the file names in the directory and judging the files and directories in PHP. The editor thinks it is quite good, so I will share it with you now and give it as a reference for everyone. Let’s follow the editor and take a look.

1. PHP gets all the file names in the directory

1. Open the directory handle of the directory to be operated

Code example:

//打开当前目录下的目录pic下的子目录common。
$handler = opendir('pic/common');
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2. Loop to read all files in the directory

Code example:

/*其中$filename = readdir($handler)
每次循环时将读取的文件名赋值给$filename,$filename !== false。
一定要用!==,因为如果某个文件名如果叫'0′,或某些被系统认为是代表false,用!=就会停止循环
*/
while( ($filename = readdir($handler)) !== false ) 
{
 //略过linux目录的名字为'.'和‘..'的文件
 if($filename != “.” && $filename != “..”)
 {  
  //输出文件名
   echo $filename;
  }
}
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3. Close the directory

Code example:

closedir($handler);
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2, PHP file and directory judgment function

<?php
//检查上级目录下的目标对象logo.jpg是否是文件。
$checkResult = is_file(&#39;../logo.jpg&#39;);
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Description: If the target object is a file, the system returns true, otherwise it returns false.

Code example:

<?php
//检查上级目录下的目标对象logo.jpg是否是目录。
$checkResult = is_dir(&#39;../logo.jpg&#39;);
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Description: Returns true if the target object is a directory system, otherwise returns false.

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