Python uses for loop to sort elements in a list

高洛峰
Release: 2017-03-10 18:48:45
Original
6756 people have browsed it

This article introduces how Python uses a for loop to sort elements in a list

list = [13, 22, 6, 99, 11]
for m in range(len(list)-1):
    for n in range(m+1, len(list)):
        if list[m]> list[n]:
            temp = list[n]
            list[n] = list[m]
            list[m] = temp
print list
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Result:

[6, 11, 13, 22, 99]


Analysis:

list = [13, 22, 6, 99, 11]
for i in range(len(list)-1):
    for j in range (i+1,len(list)):
#        print str(i)
#        print "init--" + str(j)
        print '本次进行比较的list下标值' + str(i),str(j)
        if list[i] > list[j]:
#            print i,j
#            print '-----' + str(list[i]) + str(list[j]) + '-------'
            T = list[j]
            list[j]= list[i]
            list[i]=T
#            print T 
#            print list[i],list[j]
            print '********内部的一次循环***************'
        print list 
    print  list
    print '++++++++本次内部循环结束+++++++\n\n'
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--You can see the cycle process from the printed information--

Result:

本次进行比较的list下标值0 1
[13, 22, 6, 99, 11]
本次进行比较的list下标值0 2
********内部的一次循环***************
[6, 22, 13, 99, 11]
本次进行比较的list下标值0 3
[6, 22, 13, 99, 11]
本次进行比较的list下标值0 4
[6, 22, 13, 99, 11]
[6, 22, 13, 99, 11]
++++++++本次内部循环结束+++++++
 
 
本次进行比较的list下标值1 2
********内部的一次循环***************
[6, 13, 22, 99, 11]
本次进行比较的list下标值1 3
[6, 13, 22, 99, 11]
本次进行比较的list下标值1 4
********内部的一次循环***************
[6, 11, 22, 99, 13]
[6, 11, 22, 99, 13]
++++++++本次内部循环结束+++++++
 
 
本次进行比较的list下标值2 3
[6, 11, 22, 99, 13]
本次进行比较的list下标值2 4
********内部的一次循环***************
[6, 11, 13, 99, 22]
[6, 11, 13, 99, 22]
++++++++本次内部循环结束+++++++
 
 
本次进行比较的list下标值3 4
********内部的一次循环***************
[6, 11, 13, 22, 99]
[6, 11, 13, 22, 99]
++++++++本次内部循环结束+++++++
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