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Two ways to randomly generate verification codes using Python

高洛峰
Release: 2017-03-16 17:18:56
Original
2363 people have browsed it

There are many ways to randomly generate verification codes in Python. Today I will list two for you. You can also modify it on this basis and design a verification code method that suits you

Method 1:

Use the range method. For students who are unclear about the range method, please refer to the article "range() function developed in python"

# -*- coding: utf-8 -*-
import random
def generate_verification_code(len=6):
    ''' 随机生成6位的验证码 '''
    # 注意: 这里我们生成的是0-9A-Za-z的列表,当然你也可以指定这个list,这里很灵活
    # 比如: code_list = ['P','y','t','h','o','n','T','a','b'] # PythonTab的字母
    code_list = [] 
    for i in range(10): # 0-9数字
        code_list.append(str(i))
    for i in range(65, 91): # 对应从“A”到“Z”的ASCII码
        code_list.append(chr(i))
    for i in range(97, 123): #对应从“a”到“z”的ASCII码
        code_list.append(chr(i))
    myslice = random.sample(code_list, len)  # 从list中随机获取6个元素,作为一个片断返回
    verification_code = ''.join(myslice) # list to string
    return verification_code
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Method 2:

Use the randint method

# -*- coding: utf-8 -*-
import random
def generate_verification_code_v2():
    ''' 随机生成6位的验证码 '''
    code_list = []
    for i in range(2):
        random_num = random.randint(0, 9) # 随机生成0-9的数字
        # 利用random.randint()函数生成一个随机整数a,使得65<=a<=90
        # 对应从“A”到“Z”的ASCII码
        a = random.randint(65, 90)
        b = random.randint(97, 122)
        random_uppercase_letter = chr(a)
        random_lowercase_letter = chr(b)
        code_list.append(str(random_num))
        code_list.append(random_uppercase_letter)
        code_list.append(random_lowercase_letter)
    verification_code = &#39;&#39;.join(code_list)
    return verification_code
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Test:

code = generate_verification_code(6)
code2 = generate_verification_code_v2()
print code
print code2
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Output result:

Glc5Tr
Hr6t7B
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I personally prefer the first method, which is more flexible and can set the verification code length at will.

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