The following are some Python practical tips and tools that I have collected in recent years. I hope they can be helpful to you.
x = 6 y = 5 x, y = y, x print x >>> 5 print y >>> 6
print "Hello" if True else "World" >>> Hello
The last one below This method is very cool when binding two objects of different types.
nfc = ["Packers", "49ers"] afc = ["Ravens", "Patriots"] print nfc + afc >>> ['Packers', '49ers', 'Ravens', 'Patriots'] print str(1) + " world" >>> 1 world print `1` + " world" >>> 1 world print 1, "world" >>> 1 world print nfc, 1 >>> ['Packers', '49ers'] 1
#除后向下取整 print 5.0//2 >>> 2 # 2的5次方 print 2**5 >> 32
Pay attention to the division of floating point numbers
print .3/.1 >>> 2.9999999999999996 print .3//.1 >>> 2.0
This is one of the few languages I have seen that is so awesome Simple method
x = 2 if 3 > x > 1: print x >>> 2 if 1 0: print x >>> 2
Iterate two lists simultaneously
nfc = ["Packers", "49ers"] afc = ["Ravens", "Patriots"] for teama, teamb in zip(nfc, afc): print teama + " vs. " + teamb >>> Packers vs. Ravens >>> 49ers vs. Patriots
Indexed list iteration
teams = ["Packers", "49ers", "Ravens", "Patriots"] for index, team in enumerate(teams): print index, team >>> 0 Packers >>> 1 49ers >>> 2 Ravens >>> 3 Patriots
Given a list, we can The method of brushing to select an even number list:
numbers = [1,2,3,4,5,6] even = [] for number in numbers: if number%2 == 0: even.append(number)
changes to the following:
numbers = [1,2,3,4,5,6] even = [number for number in numbers if number%2 == 0]
Isn’t it awesome, haha.
Similar to list comprehension, a dictionary can do the same job:
teams = ["Packers", "49ers", "Ravens", "Patriots"] print {key: value for value, key in enumerate(teams)} >>> {'49ers': 1, 'Ravens': 2, 'Patriots': 3, 'Packers': 0}
Initialize the value of the list
items = [0]*3 print items >>> [0,0,0]
Convert the list to String
teams = ["Packers", "49ers", "Ravens", "Patriots"] print ", ".join(teams) >>> 'Packers, 49ers, Ravens, Patriots'
I admit that the try/except code is not elegant, but here is a simple method, try to find the key in the dictionary, if not found The corresponding alue will be set to its variable value using the second parameter.
data = {'user': 1, 'name': 'Max', 'three': 4} try: is_admin = data['admin'] except KeyError: is_admin = False
Replace with this:
data = {'user': 1, 'name': 'Max', 'three': 4} is_admin = data.get('admin', False)
Sometimes, you only need some of the elements in a list. Here are some ways to get a subset of a list.
x = [1,2,3,4,5,6] #前3个 print x[:3] >>> [1,2,3] #中间4个 print x[1:5] >>> [2,3,4,5] #最后3个 print x[3:] >>> [4,5,6] #奇数项 print x[::2] >>> [1,3,5] #偶数项 print x[1::2] >>> [2,4,6]
Some time ago Jeff Atwood promoted a simple programming exercise called FizzBuzz. The question is quoted as follows:
Write a The program prints the numbers 1 to 100, replacing the number with "Fizz" for multiples of 3, "Buzz" for multiples of 5, and "FizzBuzz" for numbers that are both multiples of 3 and 5. Here is a short, interesting way to solve this problem:for x in range(101): print"fizz"[x%3*4::]+"buzz"[x%5*4::] or x
from collections import Counter print Counter("hello") >>> Counter({'l': 2, 'h': 1, 'e': 1, 'o': 1})
from itertools import combinations teams = ["Packers", "49ers", "Ravens", "Patriots"] for game in combinations(teams, 2): print game >>> ('Packers', '49ers') >>> ('Packers', 'Ravens') >>> ('Packers', 'Patriots') >>> ('49ers', 'Ravens') >>> ('49ers', 'Patriots') >>> ('Ravens', 'Patriots') False == True
False = True if False: print "Hello" else: print "World" >>> Hello
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