How to use Python's *args and **kwargs

*args represents any multiple unnamed parameters, which is a tuple; **kwargs represents keyword parameters, which is a dict.

def fun(*args, **kwargs):
    print 'args = ', args
    print 'kwargs = ', kwargs
    print '###'
if name == 'main':
    foo(1,2,3,4)
    foo(a=1,b=2,c=3)
    foo(1,2,3,4, a=1,b=2,c=3)
    foo('a', 1, None, a=1, b='2', c=3)

The output results are as follows:

args =  (1, 2, 3, 4)
kwargs =  {}
###
args =  ()
kwargs =  {'a': 1, 'c': 3, 'b': 2}
###
args =  (1, 2, 3, 4)
kwargs =  {'a': 1, 'c': 3, 'b': 2}
###
args =  ('a', 1, None)
kwargs =  {'a': 1, 'c': 3, 'b': '2'}
###

As you can see, these two are variable parameters in python .

Note: When using *args and **kwargs at the same time, the *args parameter must be listed before **kwargs, like foo(a=1, b='2', c=3, a', 1, None, ) will prompt Syntax error"SyntaxError: non-keyword arg after keyword arg" if called in this way.

def fun2(param1, *args, **kwargs):
    print 'param1 = ', param1
    print 'args = ', args
    print 'kwargs = ', kwargs
    print '###'
fun2(1, 2, 3, 4, a=1,b=2,c=3)

Output result:

param1 =  1
args =  (2,3,4)
kwargs =  {'a': 1, 'c': 3, 'b': 2}
###

1 is assigned to param1, the remaining 2, 3, and 4 are assigned to *args, and the others are assigned to **kwargs

There is also a very beautiful usage, which is to create a dictionary:

def kw_dict(**kwargs):
    return kwargs
print kw_dict(a=1,b=2,c=3)

Result:

{'a':1, 'b':2, 'c':3}

In fact, there is a dict class in python. Use dict(a=1,b=2,c=3) to create a dictionary.

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