


Detailed explanation of the code example of ASP.NET using ajax to implement the function of partially refreshing the page in paging
It is also very simple to use the ajax method to implement paging, mainly two, ContentTemplate and Trigger. First throw the listView into the ContentTemplate. Then add asp:AsyncPostBackTrigger to the Trigger and point the ID to the previous paging control DataPager control. For the specific implementation code, you can refer to this article
It is very easy to implement paging in listview. ListView paging is very simple, just add a DataPager control and assign the ID of the ListView. That's how I wrote it in the beginning. (Some people on the Internet say that this is pseudo-pagination?)
<asp:ListView ID="newBlogItems" runat="server" DataSourceID="AccessDataSource1" ViewStateMode="Disabled"> <ItemTemplate> <li class="newBlogItem"> ..... </li> </ItemTemplate> </asp:ListView> <asp:DataPager ID="DataPager1" runat="server" PageSize="15" PagedControlID="newBlogItems" ViewStateMode="Disabled"> <Fields> <asp:NextPreviousPagerField ButtonType="Link" ShowFirstPageButton="True" ShowNextPageButton="False" ShowPreviousPageButton="False" /> <asp:NumericPagerField /> <asp:NextPreviousPagerField ButtonType="Link" ShowLastPageButton="True" ShowNextPageButton="False" ShowPreviousPageButton="False" /> </Fields> </asp:DataPager>
However, after writing this, the effect of clicking pagination is to refresh the entire page. After refreshing, the page will jump around, which is of course unfriendly, so it needs to be partially When updating the page, I first thought of the jquery plug-in, so I downloaded the JPAGES plug-in from the Internet. After playing with it for a long time, I still couldn't get it, and I didn't know where the error was. . . So I gave up the trap and decided to use ajax! .
It’s very simple to use the ajax method. There are three steps to install the elephant in the refrigerator.
1. Introduce the ajax control scriptManager and place it in the form.
2. Introduce ajax control UpdatePanel.
3. Edit UpdatePanel content.
There are mainly two, ContentTemplate and Trigger. First throw the listView into the ContentTemplate. Then add asp:AsyncPostBackTrigger to the Trigger and point the ID to the previous paging control DataPager control, and that's it. The code is as follows:
<asp:UpdatePanel runat="server"> <ContentTemplate> <%--数据源--%> <asp:AccessDataSource ID="AccessDataSource1" runat="server" DataFile="C:\storage\users.accdb" SelectCommand="SELECT [userName], [blogTitle], [blogTime], [blogUrl],[statis] FROM [blog] ORDER BY [blogTime] DESC"></asp:AccessDataSource> <asp:ListView ID="newBlogItems" runat="server" DataSourceID="AccessDataSource1" ViewStateMode="Disabled"> <ItemTemplate> <li class="newBlogItem"> 此处略去1000字 </li> </ItemTemplate> </asp:ListView> <asp:DataPager ID="DataPager1" runat="server" PageSize="15" PagedControlID="newBlogItems" ViewStateMode="Disabled"> <Fields> <asp:NextPreviousPagerField ButtonType="Link" ShowFirstPageButton="True" ShowNextPageButton="False" ShowPreviousPageButton="False" /> <asp:NumericPagerField /> <asp:NextPreviousPagerField ButtonType="Link" ShowLastPageButton="True" ShowNextPageButton="False" ShowPreviousPageButton="False" /> </Fields> </asp:DataPager> </ContentTemplate> <Triggers> <asp:AsyncPostBackTrigger ControlID="DataPager1"/> </Triggers> </asp:UpdatePanel>
The above is the detailed content of Detailed explanation of the code example of ASP.NET using ajax to implement the function of partially refreshing the page in paging. For more information, please follow other related articles on the PHP Chinese website!

Hot AI Tools

Undresser.AI Undress
AI-powered app for creating realistic nude photos

AI Clothes Remover
Online AI tool for removing clothes from photos.

Undress AI Tool
Undress images for free

Clothoff.io
AI clothes remover

AI Hentai Generator
Generate AI Hentai for free.

Hot Article

Hot Tools

Notepad++7.3.1
Easy-to-use and free code editor

SublimeText3 Chinese version
Chinese version, very easy to use

Zend Studio 13.0.1
Powerful PHP integrated development environment

Dreamweaver CS6
Visual web development tools

SublimeText3 Mac version
God-level code editing software (SublimeText3)

Hot Topics

Title: Methods and code examples to resolve 403 errors in jQuery AJAX requests. The 403 error refers to a request that the server prohibits access to a resource. This error usually occurs because the request lacks permissions or is rejected by the server. When making jQueryAJAX requests, you sometimes encounter this situation. This article will introduce how to solve this problem and provide code examples. Solution: Check permissions: First ensure that the requested URL address is correct and verify that you have sufficient permissions to access the resource.

jQuery is a popular JavaScript library used to simplify client-side development. AJAX is a technology that sends asynchronous requests and interacts with the server without reloading the entire web page. However, when using jQuery to make AJAX requests, you sometimes encounter 403 errors. 403 errors are usually server-denied access errors, possibly due to security policy or permission issues. In this article, we will discuss how to resolve jQueryAJAX request encountering 403 error

Using Ajax to obtain variables from PHP methods is a common scenario in web development. Through Ajax, the page can be dynamically obtained without refreshing the data. In this article, we will introduce how to use Ajax to get variables from PHP methods, and provide specific code examples. First, we need to write a PHP file to handle the Ajax request and return the required variables. Here is sample code for a simple PHP file getData.php:

How to solve the problem of jQueryAJAX error 403? When developing web applications, jQuery is often used to send asynchronous requests. However, sometimes you may encounter error code 403 when using jQueryAJAX, indicating that access is forbidden by the server. This is usually caused by server-side security settings, but there are ways to work around it. This article will introduce how to solve the problem of jQueryAJAX error 403 and provide specific code examples. 1. to make

Ajax (Asynchronous JavaScript and XML) allows adding dynamic content without reloading the page. Using PHP and Ajax, you can dynamically load a product list: HTML creates a page with a container element, and the Ajax request adds the data to that element after loading it. JavaScript uses Ajax to send a request to the server through XMLHttpRequest to obtain product data in JSON format from the server. PHP uses MySQL to query product data from the database and encode it into JSON format. JavaScript parses the JSON data and displays it in the page container. Clicking the button triggers an Ajax request to load the product list.

How to use Ajax functions to achieve asynchronous data interaction With the development of the Internet and Web technology, data interaction between the front end and the back end has become very important. Traditional data interaction methods, such as page refresh and form submission, can no longer meet user needs. Ajax (Asynchronous JavaScript and XML) has become an important tool for asynchronous data interaction. Ajax enables the web to use JavaScript and the XMLHttpRequest object

Understanding the Ajax Framework: Explore five common frameworks, requiring specific code examples Introduction: Ajax is one of the essential technologies in modern web application development. It has become an indispensable part of front-end development because of its features such as supporting asynchronous data interaction and improving user experience. In order to better understand and master the Ajax framework, this article will introduce five common Ajax frameworks and provide specific code examples to help readers gain an in-depth understanding of the usage and advantages of these frameworks. 1. jQuery jQuery is currently the most

In order to improve Ajax security, there are several methods: CSRF protection: generate a token and send it to the client, add it to the server side in the request for verification. XSS protection: Use htmlspecialchars() to filter input to prevent malicious script injection. Content-Security-Policy header: Restrict the loading of malicious resources and specify the sources from which scripts and style sheets are allowed to be loaded. Validate server-side input: Validate input received from Ajax requests to prevent attackers from exploiting input vulnerabilities. Use secure Ajax libraries: Take advantage of automatic CSRF protection modules provided by libraries such as jQuery.
