Detailed explanation of python3 set (set)

迷茫
Release: 2017-03-25 13:18:45
Original
1459 people have browsed it

add(add elements)

name = set(['Tom','Lucy','Ben'])
name.add('Juny')print(name)#输出:{'Lucy', 'Juny', 'Ben', 'Tom'}
Copy after login

clear(clear all elements)

name = set(['Tom','Lucy','Ben'])
name.clear()print(name)#输出:set()
Copy after login

copy(copy set collection)

name = set(['Tom','Lucy','Ben'])
new_name = name.copy()print(new_name)#输出:{'Tom', 'Lucy', 'Ben'}
Copy after login

difference(returns different elements in two or more sets and generates a new set)

A = set([2,3,4,5])
B = set([3,4])
C = set([2])
n = n1.difference(n2,n3)
print(n)
#输出:{5}
#返回A集合里面,在B和C集合中没有的元素,并生成新的集合
Copy after login

difference_updatedelete In the A set, the elements that exist in the B set)

A = set([2,3,4,5])
B = set([4,5])
A.difference_update(B)
print(A)

#输出:{2, 3}
Copy after login

discard(remove the element)

n = set([2,3,4])
n.discard(3)print(n)#输出:{2, 4}
Copy after login

intersection(take the intersection and generate a new set)

n1 = set([2,3,4,5])
n2 = set([4,5,6,7])
n = n1.intersection(n2)print(n)#输出:{4, 5}
Copy after login

intersection_update(Get the intersection and modify the original set)

n1 = set([2,3,4,5])
n2 = set([4,5,6,7])
n1.intersection_update(n2)print(n1)#输出:{4, 5}
Copy after login

isdisjoint(Judge the intersection, return False if it is, True if not)

n1 = set([2,3,4,5])
n2 = set([4,5,6,7])print(n1.isdisjoint(n2))#输出:False
Copy after login

issubset(Judge the subset)

A = set([2,3])
B = set([2,3,4,5])print(A.issubset(B))#输出:True#A是B的子集
Copy after login

issuperset(Judge the parent set)

A = set([2,3])
B = set([2,3,4,5])print(B.issuperset(A))# 输出:True#B是A的父集
Copy after login

pop(Randomly remove an element)

n = set([2,3,4,5])
n1 = n.pop()print(n,n1)# 输出:{3, 4, 5} 2
Copy after login

remove(Remove the specified element)

n = set([2,3,4,5])
n.remove(2)print(n)# 输出:{3, 4, 5}
Copy after login

symmetric_difference(Get the intersection , and generate a new set)

A = set([2,3,4,5])
B = set([4,5,6,7])print(A.symmetric_difference(B))# 输出:{2, 3, 6, 7}
Copy after login

symmetric_difference_update(take the intersection, change the original set)

A = set([2,3,4,5])
B = set([4,5,6,7])
A.symmetric_difference_update(B)print(A)# 输出:{2, 3, 6, 7}
Copy after login

union(take the union, and generate a new set)

A = set([2,3,4,5])
B = set([4,5,6,7])print(A.union(B))# 输出:{2, 3, 4, 5, 6, 7}
Copy after login

update(take the union and change the original set)

A = set([2,3,4,5])
B = set([4,5,6,7])
A.update(B)print(A)# 输出:{2, 3, 4, 5, 6, 7}
Copy after login

The above is the detailed content of Detailed explanation of python3 set (set). For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!