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php中判断文件空目录是否有读写权限的函数代码_php技巧

May 17, 2016 am 09:09 AM

is_writable用来处理,记住 PHP 也许只能以运行 webserver 的用户名(通常为 \'nobody\')来访问文件。不计入安全模式的限制。
Example #1 is_writable() 例子

复制代码 代码如下:

$filename = 'test.txt';
if (is_writable($filename)) {
echo 'The file is writable';
} else {
echo 'The file is not writable';
}
?>

上面的函数有一个问题就是filename 必需。规定要检查的文件 ,必须是文件啊,目录不可判断,下面我们来判断空目录。
实例1
该功能非常常用,特别在一些需要生成静态文件的项目中,一个目录是否可以,关乎到是否对该目录有创建文件删除文件的权限
复制代码 代码如下:

/*
问题出现:如何检查一个目录是否可写,如何目录下还有目录和文件,那么都要检查
思路:
(1)首先先写出检查空目录是否可写的算法:
在该目录中生成一个文件,如果不能生成,表明该目录没有写的权限
(2)使用递归的办法来进行检查
代码实现:
*/
set_time_limit(1000);
function check_dir_iswritable($dir_path){
$dir_path=str_replace('\','/',$dir_path);
$is_writale=1;
if(!is_dir($dir_path)){
$is_writale=0;
return $is_writale;
}else{
$file_hd=@fopen($dir_path.'/test.txt','w');
if(!$file_hd){
@fclose($file_hd);
@unlink($dir_path.'/test.txt');
$is_writale=0;
return $is_writale;
}
$dir_hd=opendir($dir_path);
while(false!==($file=readdir($dir_hd))){
if ($file != "." && $file != "..") {
if(is_file($dir_path.'/'.$file)){
//文件不可写,直接返回
if(!is_writable($dir_path.'/'.$file)){
return 0;
}
}else{
$file_hd2=@fopen($dir_path.'/'.$file.'/test.txt','w');
if(!$file_hd2){
@fclose($file_hd2);
@unlink($dir_path.'/'.$file.'/test.txt');
$is_writale=0;
return $is_writale;
}
//递归
$is_writale=check_dir_iswritable($dir_path.'/'.$file);
}
}
}
}
return $is_writale;
}

上面实例主要是fopen去在目录创建文件或在文件中写内容,这样就可以判断目录的读写权限了。
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