After completing my graduate defense, I began to continue working hard for a career change. Xiaobai is going to struggle, come on. This article is quoted from the JS core series: A brief discussion of the scope of functions.
In a function, this always points to the owner object of the current function. The specific point of this can only be determined at runtime, and its calling object can only be known.
window.name = "window"; function f(){ console.log(this.name); } f();//输出window var obj = {name:'obj'}; f.call(obj); //输出obj
When f() is executed, the caller of f() is the window object, so "window" is output.
f.call(obj) puts f() on the obj object and executes it, which is equivalent to obj.f(). At this time, this in f is obj, so the output is "obj".
code1:
var foo = "window"; var obj = { foo : "obj", getFoo : function(){ return function(){ return this.foo; }; } }; var f = obj.getFoo(); console.log(1+":"+f()); //输出window
code2:
var foo = "window"; var obj = { foo : "obj", getFoo : function(){ var that = this; return function(){ return that.foo; }; } }; var f = obj.getFoo(); console.log(f()); //输出obj
code1:
Executing var f = obj.getFoo() returns an anonymous function, equivalent to:
var f = function(){
Return this.foo;
}
f() is equivalent to window.f(), so this in f points to the window object, and this.foo is equivalent to window.foo, so f() returns "window"
code2:
Executing var f = obj.getFoo() also returns an anonymous function, that is:
var f = function(){
return that.foo;
}
The only difference is that this in f becomes that. Before knowing which object that is, first determine the scope chain of f: f->getFoo-> ;window and search for that on the chain, you can find that that refers to this in getFoo, and this in getFoo points to the caller of its runtime. From var f = obj.getFoo(), we know that this points to is an obj object, so that.foo is equivalent to obj.foo, so f() returns "obj".
Students who are unclear about the scope chain can refer to JavaScript from Scope to Closure.
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