Example code sharing of how to determine whether a year is an ordinary year or a leap year in Java

This article mainly introduces Java in detail to determine whether a given year is an ordinary year or a leap year. It has a certain reference value. Interested friends can refer to it

Requirements:

* Determine whether the year entered by the user is an ordinary year or a leap year

Implementation code:

import java.util.Scanner;

/**
 * 要求：
 *  判断用户输入的年份是平年还是闰年
 * @author Administration
 *
 */
public class Judge {
 public static void main(String[] args) {
  Scanner input = new Scanner(System.in);
  System.out.println("请输入一个年份：");
  long year = input.nextLong();
  //闰年需要满足的条件：能被4整除但不能被100整除，或者能被400整除，满足其中一个即可
  if((year%4==0 && year%100!=0) || year%400==0 ){
   System.out.println(year+"年是闰年！");
  }else{
   System.out.println(year+"年是平年！");
  }
 }
}

Running result:

Please enter a year:
1000
The year 1000 is an ordinary year!

Please enter a year:
2000
2000 is a leap year!

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