Detailed explanation of an example of Java programming question

There are five students, each student has grades for 3 courses. Enter the above data from the keyboard (including student number, name, grades for the three courses), and calculate the average grade. The original data and the calculated The average score is stored in the disk file "stud".

public class Example50 {
public static void main(String[] args) {
stud();
}

public static void stud() {
Scanner ss = new Scanner(System.in);
String[][] a = new String[5][6];
for (int i = 1; i < 6; i++) {
System.out.print ("Please enter the" + i + "student's student number:");
A [i - 1] [0] = ss.nextline ();
System. out.print("Please enter the name of the " + i + " student: ");
        a[i - 1][1] = ss.nextLine();
            for (int j = 1; j < 4; j++) {
            System.out.print("Please enter the student's " + j + "th grade: "); ss.nextLine();
      }
          System.out.println("\n");
for (int i = 0; i < 5; i++) {
sum = 0;
for (int j = 2; j < 5; j++) {
sum = sum + Integer.parseInt(a[i][j]);
       }
          avg = (float) sum / 3;
                a[i][5] = String.valueOf(avg);
}
// The following disk files
String s1;
Try {
File F = New File ("E: \\ Eclipse Workplace \\ Java classic algorithm \\ src \\ stud.txt.txt ");
if (f.exists()) {
System.out.println("The file does not exist");
if (f.exists());
System.out.println("The file does not exist. Creating file");
                                                                                                                                      . i < 5; i++) {
output.write (s1);
}
System.out.println ();
}
Output.close ();
System.out.println ("The data has been written in E disk file stud! ");
    } catch (Exception e) {
            e.printStackTrace();
                }
                                                               

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