Create a Jersey REST service based on Maven
REST service based on JavaSE
-
Create project
We prefer to use the prototype with archetypeGroupId as org.glassfish.jersey.archetypes and archetypeArtifactId as jersey-quickstart-grizzly2 to create a REST service Project, use IDEA to create the project as follows:
##After clicking OK, use the original model to create the project.
- Running Service
After the project is created, the original model has created a REST service by default. We can start the REST service directly, enter the root directory of the project, and execute the following command to build and start the service:
mvnpackage
##mvnexec:java
The REST service will be started, and you can stop the service at any time by pressing the Enter key. The output is as follows:
##June 19, 2017 11:12:23 PM org. glassfish.grizzly.http.server.NetworkListener startMessage: Started listener bound to [localhost:8080]
June 19, 2017 11:12:23 PM org.glassfish.grizzly.http.server.HttpServer start
Information: [HttpServer] Started.
Jersey app started with WADL available at http://localhost:8080/myapp/application.wadl
##Hit enter to stop it…
also provides
WADL. By accessing application.wadl, you can obtain the interface published by the current REST service:
base="http://localhost:8080/myapp/"> # ;path= "myresource">#
"getIt"id= name="GET"># ##
##
through #
##Access service
can be accessed directlyhttp://localhost:8080/myapp/myresource
You can access the REST service. If you directly access the REST service,Got it! will be output.
project instructionCommand to start the servicemvnexec: java, this command actually calls one defined by the exec-maven-plugin plug-in The goal whose value is java is used to trigger the main function in mainClass. The plug-in configuration is as follows:
org.codehaus.mojo #
exec-maven-plugin ##
1.2.1 ## #
#
#
## .rest.Main
#
REST service class is MyResource, the resource path is defined in @Path, and GET is defined in @GET Method getIt(), the response type defined in @Produces is an ordinary string, the sample code is as follows:
@Path("myresource")
##public classMyResource {
@GET##
@GET# public String getIt() {
return"Got it!";
}
}
##The unit test class MyResourceTest of the REST service, in the unit test class, is required before executing the unit test Start the service and use the method defined in JerseyClient to call the REST service. The sample code is as follows:
##public classMyResourceTest {##
privateHttpServer server; ;
##voidsetUp() throws Exception {
// Start the Server Server = Main.startserver ();
// create the client
Client c = ClientBuilder.newClient();
// uncomment the following line if you want to enable
// support for JSON in the client (you also have to uncomment
// dependency on jersey-media-json module in pom.xml and Main.startServer())
// --
// c.configuration().enable(new org.glassfish.jersey.media.json.JsonJaxbFeature());
target = c.target(Main.BASE_URI);
}
@After
publicvoidtearDown() throws Exception {
server.stop();
}
@Test
publicvoidtestGetIt() {
String responseMsg = target.path("myresource").request().get(String.class);
assertEquals("Got it!", responseMsg);
}
}
Based on Servlet container service
Create projectWe prefer to use the prototype with archetypeGroupId as org.glassfish.jersey.archetypes and archetypeArtifactId as jersey-quickstart-webapp prototype, create a REST service project, use IDEA to create the project as follows:
Running ServiceSince this is a Web project and does not have a main function, it must be deployed into a Servlet container before it can be run. , we need to configure Tomcat, the configuration of IDEA is as follows:
-
Click ## of the Run menu #EditConfiguration, add Tomcat service configuration in the opened form, specify the installation directory of Tomcat, and set the current site's The name of the deployed virtual directory is as follows:
After clicking OK, the Servlet container is configured and the service can be run
Access the serviceAfter the service is started, we can accesshttp://localhost:8080/RESTWebAPP/webapi /myresource to call the REST service will output Got it!
Project DescriptionThe name of the Web root directory is webapp, the default Servlet container version is 2.5, and the WEB-INF/web.xml file is configured to configure the REST service. The web.xml configuration is as follows:
version="1.0"encoding="UTF-8"? >
#
see implementation details -->
version="2.5"xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation=" http://java.sun.com/xml/ns/javaee "> ##
Jersey Web Application##
org.glassfish.jersey.servlet.ServletContainer ## & LT; Param-Name & GT; ## jersey.config. Orvider.packages & LT
org.drsoft.rest ##
1Jersey Web Application /webapi/*
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