Analysis of problems arising from foreach reference in php
1, foreach is the loop output of php on the array.
Example:
$arr = array("1"=>"111","2"=>"222","3"=>"333"); foreach($arr as $key=>$value) { echo $key."=>".$value."\n"; }
The result is as follows:
1=>111 2=>222 3=>333
2, slightly modified:
foreach($arr as $key=>$value) { //echo $key."=>".$value."\n"; $key = &$arr[$key]; } print_r($arr);
The result is as follows:
Array ( [1] => 2 [2] => 3 [3] => 333 )
Code explanation :
We found that the original array was modified. Why? Let's study it.
The key part in the code is: $key = &$arr[$key];
$key is the reference of $arr[$key], that is , when $key is modified, $arr[$key] is also modified to the corresponding value.
First of all, we need to understand the principle of foreach. It assigns the values of the array to $key and $value respectively;
So, $key and $value are also ordinary ones. variable.
Next analysis, in the first loop, $key = &$arr[$key]; means &$arr[1] points to the variable $key.
When the foreach loop reaches the second pass, first, $key is assigned a value of 2. At this time, pay attention again, $key = &$arr[$key];
The result is :$arr[1] is assigned the new $key at this time, which is 2.
After the second loop ends, the original array becomes:
Array ( [1] => 2 [2] => 222 [3] => 333 )
Similarly, After the third cycle ends, it will be:
Array ( [1] => 2 [2] => 3 [3] => 333 )
At this point, it has been roughly explained.
3, in order to understand more clearly, the assignment process in foreach, we can do this:
$arr = array("1"=>"111","2"=>"222","3"=>"333"); foreach($arr as $key=>$value) { $key = &$arr[$key]; $key = "hello"; unset($key); print_r($arr); }
The result is as follows:
Array ( [1] => hello [2] => 222 [3] => 333 ) Array ( [1] => hello [2] => hello [3] => 333 ) Array ( [1] => hello [2] => hello [3] => hello )
Code explanation:
We directly assign the value "hello" to $key in each loop, so as not to affect it, and then release the $key variable.
This should make it clearer.
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