The usage difference between break and continue in php

Generally speaking, after the program enters the loop body, all statements in the loop body will be executed before the next loop judgment. The break and continue statements can terminate the loop or ignore certain loops.

break: This statement causes the program to terminate the loop containing it and proceed to the next phase of the program (the statement following the entire loop), i.e., instead of jumping to The next loop cycle will exit the loop instead. If the break statement is contained in a nested loop, it only breaks out of the innermost loop.

#include<stdio.h>
int main()
{
int res=0;
int i=0;
int n=0;
printf("test break and continue\n");
for(i=0;i<6;i++)
{
printf("start...\n");
if(i==3)
        {
        printf("break \n");
        break;
        printf("break after\n");
        //printf("continue \n");
        //continue;
        //printf("continue after\n");
        }


printf("now i = %d\n",i);
}
printf("test over !!!\n");
return 0;
}

$ gcc -o bc bc.c
$ ./bc
test break and continue
start...
now i = 0
start...
now i = 1
start...
now i = 2
start...
break 
test over !!!
$

Nested loop (break) ：

#include<stdio.h>
int main()
{
int res=0;
int i=0;
int n=0;
printf("test break and continue\n");
for(i=0;i<6;i++)
{
printf("start...\n");
for(n=0;n<6;n++)
{
if(n==3)
        {
        printf("break \n");
        break;
        //printf("continue \n");
        //continue;
        }
printf("now n= %d\n",n);
}
if(i==3)
        {
        printf("break \n");
        break;
        printf("break after\n");
        //printf("continue \n");
        //continue;
        //printf("continue after\n");
        }


printf("now i = %d\n",i);
}
printf("test over !!!\n");
return 0;
}

$ gcc -o bc bc.c
$ ./bc
test break and continue
start...
now n= 0
now n= 1
now n= 2
break 
now i = 0
start...
now n= 0
now n= 1
now n= 2
break 
now i = 1
start...
now n= 0
now n= 1
now n= 2
break 
now i = 2
start...
now n= 0
now n= 1
now n= 2
break 
break 
test over !!!
$

continue:When there is this statement in the loop statement, when the program runs to this statement, Instead of executing the statement after continue in the loop body, it jumps to the next loop entrance to execute the next loop. If a continue statement is contained within a nested loop, it only affects the innermost loop that contains it.

#include<stdio.h>

int main()
{
int res=0;
int i=0;
int n=0;
printf("test break and continue\n");
for(i=0;i<6;i++)
{
printf("start...\n");
if(i==3)
        {
        //printf("break \n");
        //break;
        //printf("break after\n");
        printf("continue \n");
        continue;
        printf("continue after\n");
        }

printf("now i = %d\n",i);
}
printf("test over !!!\n");
return 0;
}

$ gcc -o bc bc.c
$ ./bc
test break and continue
start...
now i = 0
start...
now i = 1
start...
now i = 2
start...
continue 
start...
now i = 4
start...
now i = 5
test over !!!
$

Nested loop (continue):

#include<stdio.h>

int main()
{
int res=0;
int i=0;
int n=0;
printf("test break and continue\n");
for(i=0;i<6;i++)
{
printf("start...\n");

for(n=0;n<6;n++)
{
if(n==3)
        {
        //printf("break \n");
        //break;
        printf("continue \n");
        continue;
        }
printf("now n= %d\n",n);
}

if(i==3)
        {
        //printf("break \n");
        //break;
        //printf("break after\n");
        printf("continue \n");
        continue;
        printf("continue after\n");
        }

printf("now i = %d\n",i);
}
printf("test over !!!\n");
return 0;
}

$ gcc -o bc bc.c
$ ./bc
test break and continue
start...
now n= 0
now n= 1
now n= 2
continue 
now n= 4
now n= 5
now i = 0
start...
now n= 0
now n= 1
now n= 2
continue 
now n= 4
now n= 5
now i = 1
start...
now n= 0
now n= 1
now n= 2
continue 
now n= 4
now n= 5
now i = 2
start...
now n= 0
now n= 1
now n= 2
continue 
now n= 4
now n= 5
continue 
start...
now n= 0
now n= 1
now n= 2
continue 
now n= 4
now n= 5
now i = 4
start...
now n= 0
now n= 1
now n= 2
continue 
now n= 4
now n= 5
now i = 5
test over !!!
$

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