How to pass parameters to php under shell command

Usually PHP makes HTTP requests, and you can use GET or POST to receive parameters. Sometimes you need to execute PHP as a script under a shell command, such as a scheduled task. This involves the issue of how to pass parameters to php under the shell command. There are usually three ways to pass parameters.

1. Use $argv or $argc parameter to receive

<?php
/**
 * 使用 $argc $argv 接受参数
 */
 echo "接收到{$argc}个参数";
print_r($argv);

Execute

[root@DELL113 lee]# /usr/local/php/bin/php test.php
接收到1个参数
Array
(
    [0] => test.php
)
[root@DELL113 lee]# /usr/local/php/bin/php test.php a b c d
接收到5个参数Array
(
    [0] => test.php
    [1] => a
    [2] => b
    [3] => c
    [4] => d
)
[root@DELL113 lee]#

2. Use getopt Function

<?php
/**
 * 使用 getopt函数
 */
 
$param_arr = getopt(&#39;a:b:&#39;);
print_r($param_arr);

Execution

[root@DELL113 lee]# /usr/local/php/bin/php test.php -a 345
Array
(
    [a] => 345
)
[root@DELL113 lee]# /usr/local/php/bin/php test.php -a 345 -b 12q3
Array
(
    [a] => 345
    [b] => 12q3
)
[root@DELL113 lee]# /usr/local/php/bin/php test.php -a 345 -b 12q3 -e 3322ff
Array
(
    [a] => 345
    [b] => 12q3
)

3. Prompt the user to input

<?php
/**
 * 提示用户输入，类似Python
 */
fwrite(STDOUT,&#39;请输入您的博客名：&#39;);
echo &#39;您输入的信息是：&#39;.fgets(STDIN);

Execution

[root@DELL113 lee]# /usr/local/php/bin/php test.php

Please enter your blog name:
The information you entered is:
You can also do this, preventing users from entering empty information

<?php
/**
 * 提示用户输入，类似Python
 */
 
$fs = true;
 
do{
oif($fs){
fwrite(STDOUT,&#39;请输入您的博客名：&#39;);
$fs = false;
}else{
fwrite(STDOUT,&#39;抱歉，博客名不能为空，请重新输入您的博客名：&#39;);
}
 
$name = trim(fgets(STDIN));
 
}while(!$name);
 
echo &#39;您输入的信息是：&#39;.$name."\r\n";

Execute

[root@DELL113 lee]# /usr/local/php/bin/php test.php 
请输入您的博客名：
抱歉，博客名不能为空，请重新输入您的博客名：
您输入的信息是：

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