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Except for the syntax of the capturing group, other syntaxes are not verification of the capturing group_regular expression

微波
Release: 2017-06-28 13:41:44
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这篇文章主要介绍了除捕获组的语法外,其它的(?...)语法都不是捕获组的验证,需要的朋友可以参考下

在一篇正则表达式技术文档中看到下面内容:

“外需要说明的一点是,除(Expression)和(?Expression)语法外,其它的(?...)语法都不是捕获组。”
这个内容是好理解的,但疑惑的是,该文章作者在另一篇相关正则的技术文章中,其中一个这样的实例,着实让我迷惑了一番:

文本内容

<td>a</td><td>b</td>
Copy after login

正则表达式

(?is)<td>(?:(?!</td>).)*</td>
Copy after login

注意上面正则表达式的代码,他对“(?!).”进行“强制非捕获组”,我在短信中告诉他,可以这样写:(?is)((?!).)*
两天仍未见他回复,于是在回过头来研究一下他代码,起初我将重点放在“(?!)”这个括号算不算捕获组。但是在看一次上面技术文章的代码我才反应过来。他不是针对(?!)强制为非捕获组,而是将(?!).强制为非捕获组,于是我就做了下面的测试:

文本内容

<td>a</td><td>a</td>
Copy after login
Copy after login
Copy after login

正则表达式

<td>((?!</td>).)*</td><td>(\1)*</td>
Copy after login

匹配结果

<td>a</td><td>a</td>
Copy after login
Copy after login
Copy after login

这就证明,如果不对“(?!).”进行强制为非捕获组,它是会捕获的,而这个捕获,我根本不需要它。
下面,我在测试一下,除了(Expression)和(?Expression)语法外,其它的,如环视,它算不算捕获组。

文本内容

<td>a</td><td>a</td>
Copy after login
Copy after login
Copy after login

正则表达式

<td>((?!</td>).)*</td><td>(\2.)*</td>
Copy after login

匹配结果:不匹配
如有不同见解,欢迎讨论。

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