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Problems and solutions when using org json and fast json

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Release: 2017-06-29 11:28:20
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1. Differences in values
When the obtained key does not exist:
org json will throw Exception
fast json will return null
Example:
com.alibaba.fastjson.JSONObject fastJson = new com.alibaba.fastjson.JSONObject( );
String name = fastJson.getString("name");
// fastJson normal output name:null
System.out.println("name:" + name);
org.json.JSONObject orgJson = new org.json.JSONObject();
//Throw exception: org.json.JSONException: JSONObject["name"] not found.
name = orgJson.getString("name");
System.out.println("name:" + name);
2. put org json in fast json
This operation is abnormal and empty json will be put
Example:
org.json.JSONObject orgJsonAddress = new org.json.JSONObject();
orgJsonAddress.put("country", " China");
orgJsonAddress.put("province", "Henan");
orgJsonAddress.put("city", "Zhengzhou");
com.alibaba.fastjson.JSONObject fastJson = new com.alibaba.fastjson.JSONObject();
fastJson.put("name", "Qingjiang Li");
fastJson.put("sex", 1);
fastJson.put("address", orgJsonAddress);
System.out.println(fastJson.toJSONString());
Exception output:
{
"address": {},
"sex": 1,
"name": "Qingjiang Li"
}
3. put fast json in org json
This operation is normal
Example:
com.alibaba.fastjson. JSONObject fastJsonAddress = new com.alibaba.fastjson.JSONObject();
fastJsonAddress.put("country", "China");
fastJsonAddress.put("province", "Henan" );
fastJsonAddress.put("city", "Zhengzhou");
org.json.JSONObject orgJson = new org.json.JSONObject();
orgJson.put("name", "Qingjiang Li");
orgJson.put("sex", 1);
orgJson.put("address", fastJsonAddress);
System.out.println(orgJson.toString());
Output is normal:
{
"address": {
"country": "China",
"province": "Henan",
"city": "Zhengzhou"
},
"sex": 1,
"name": "Qingjiang Li"
}
Conclusion:
In the project, try to use the same kind of JSON. If you have to use both, please be careful when using it and avoid Mistakes occur due to habits.

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