Home > Web Front-end > JS Tutorial > Detailed example of how JS calculates age based on birthday

Detailed example of how JS calculates age based on birthday

怪我咯
Release: 2017-06-29 10:25:48
Original
2433 people have browsed it

This article mainly introduces the JS method of calculating age based on birthdays, involving javascript related skills in operating time. It is very simple and practical. Friends in need can refer to the following examples

Learn how to calculate age based on birthday in JS. Share it with everyone for your reference. The specific implementation method is as follows:

function parseDate(str){
 if(str.match(/^\d{4}[\-\/\s+]\d{1,2}[\-\/\s+]\d{1,2}$/)){
  return new Date(str.replace(/[\-\/\s+]/i,'/'));
 }
 else if(str.match(/^\d{8}$/)){
  return new Date(str.substring(0,4)+'/'+str.substring(4,6)+'/'+str.substring(6));
 }
 else{
  return ('时间转换发生错误!');
 }
}
function GetAgeByBrithday(birthday){
 var age=-1;
 var today=new Date();
 var todayYear=today.getFullYear();
 var todayMonth=today.getMonth()+1;
 var todayDay=today.getDate();
 var birthday=parseDate(birthday);
 if(parseDate(birthday)!='时间转换发生错误!')
 {
 birthdayYear=birthday.getFullYear();
 birthdayMonth=birthday.getMonth();
 birthdayDay=birthday.getDate();
 if(todayYear-birthdayYear<0)
 {
  alert("出生日期选择错误!");
 }
 else
 {
  if(todayMonth*1-birthdayMonth*1<0)
  {
    age = (todayYear*1-birthdayYear*1)-1;
  }
  else
  {
    if(todayDay-birthdayDay>=0)
    {//alert(thisDay+&#39;-&#39;+brithd+"_ddd");
      age = (todayYear*1-birthdayYear*1);
    }
    else
    {
      age = (todayYear*1-birthdayYear*1)-1;
    }
  }
 }
 return age*1;
 }
 else
 {
 return -1;
 }
}
Copy after login

The above is the detailed content of Detailed example of how JS calculates age based on birthday. For more information, please follow other related articles on the PHP Chinese website!

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template