opendir() FunctionOpen a directory handle. If successful, the directory handle resource is returned. Returns FALSE on failure. If the path is not a legal directory, or the directory cannot be opened due to licensing restrictions or filesystem errors, an E_WARNING level error is thrown. You can hide the error output of opendir() by adding '@' before the function name
opendir() function syntax
opendir(path,context);
Parameters | Description |
---|---|
path | Required. Specifies the directory path to be opened. |
context | Optional. Specifies the environment for directory handles. context is a set of options that modify the behavior of a directory stream. |
opendir() function example, the code is as follows:
$dirs ='./';//指定当前上当 if( is_dir( $dirs ) ) { $hanld = opendir($dirs); while (($file = readdir($hanld)) !== false) { echo "文件名: " . $file . "<br />"; } closedir($hanld); } else { echo '不是目录'; }
Output result:
File name: a
File name: b
File name:www.php.cn
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