How to use list() function in php to assign values ​​in array to variables

CleverCode found a method that returns multiple values ​​by receiving a php function . It was often used in python before, and this method is also available in PHP.

<?php

function retInfo()
{
    $name = &#39;张三&#39;;
    $age = 18;
    $sex = 1;
    return array($name,$age,$sex);
}

list($name1,$age1,$sex1) = retInfo();

echo "name:${name1},age:${age1},sex:${sex1}\r\n";


list($name2,$age2,$sex2) = array(&#39;李四&#39;,19,2);

echo "name:${name2},age:${age2},sex:${sex2}\r\n";


?>

list()

PHP list() Use one step to assign the values ​​in the array to somevariable. Like array(), list() is not a true function, but a language construct.

Syntax:

void list( mixed var, mixed ... )Note: list() can only be used on numerically indexed arrays and assumes that numerical indexing starts from 0.

Example 1:

<?php
$arr_age = array(18, 20, 25);
list($wang, $li, $zhang) = $arr_age;
echo $wang;    //输出：18
echo $zhang;    //输出：25
?>

Example 2, data table Query:

$result = mysql_query("SELECT id, username, email FROM user",$conn);
while(list($id, $username, $email) = mysql_fetch_row($result)) {
  echo "用户名：$username<br />";
  echo "电子邮箱：$email";
}

list() using array index

list() allows the use of another array to receive the values ​​assigned by the array, but when using an index array, the order of assignment is reversed from the order listed in list():

$arr_age = array(18, 20, 25);
list($a[0], $a[1], $a[2]) = $arr_age;
print_r($a);

Output The $a array structure is as follows:

Array ( [2] => 25 [1] => 20 [0] => 18 )

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