What is the difference between the usage of ternary operator and if else in JavaScript?

I tried if else first, the code is as follows:

if(n >= count-1){
n =0;
}else{
n ++;
}

After the code is written, I am going to optimize the code and change this section to three-eye. The way of writing the operator

n = n >= (count-1) ? n=0 : n++

The result is completely different

I then studied the difference between the two and summarized it in one sentence: the ternary operation has a return value, if else has no return value

Did the following test:

var n=1;
 if(n>1){
    n=0;
}else{
    n++;
}
console.log(n);

Output result: 2

Ternary operation is as follows:

var n=1;
n = n>1?0 : n++;
console.log(n);

The output result is: 1

Insert a piece of other content: The difference between ++n and n++: Simply put, n increases by 1. The difference is that n++ only adds 1 after executing the following statements; while ++n does n+1 first before executing the following statements

So what about ++n

if else statement

var n=1;
 if(n>1){
    n=0;
}else{
    ++n;
}
console.log(n);

Output result: 2

Ternary operation result

var n=1;
n = n>1?0 : ++n; 
console.log(n);

Output result is: 2

You can see the difference between if else and ternary operation~~~

There is no difference between n++ and ++n in this verification, because if else is It is after the calculation result, n will not be returned, and there is no return value.

But for ternary operations, the n value returned by n++ is n itself, and the n value returned by ++n is the result after n+1.

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