Detailed explanation of object to XML method explained by Python

This article mainly introduces Python's method of converting objects into xml. It analyzes Python object attributes, node operations and related implementation techniques for converting to xml in the form of examples. Friends in need can refer to the following

The example in this article describes the method of converting objects into xml in Python. Share it with everyone for your reference, the details are as follows:

# -*- coding:UTF-8 -*-
'''''
Created on 2010-4-20
@author: 忧里修斯
'''
import xml.etree.ElementTree as ET
import xml.dom.minidom as minidom
from addrbook.domain import Person
class Converter(object):
  '''''
     实现Python对象与xml之间的相互转换
  '''
  root = None#根节点
  def __init__(self):
    pass
  @staticmethod
  def createRoot(rootTag):
    '''''
          创建根节点
    '''
    root = ET.Element(rootTag)
    return root
  @staticmethod
  def getXmlString(element,defaultEncoding='utf-8'):
    '''''
          根据节点返回格式化的xml字符串
    '''
    try:
      rough_string = ET.tostring(element, defaultEncoding)
      reparsed = minidom.parseString(rough_string)
      return reparsed.toprettyxml(indent=" " , encoding=defaultEncoding)
    except:
      print 'getXmlString:传入的节点不能正确转换为xml，请检查传入的节点是否正确'
      return ''
  @staticmethod
  def classToElements(classobj,rootTag=None):
    '''''
          根据传入的对象的实例，根据对象的属性生成节点，返回由节点组成的列表
    classobj：对象的实例
    rootTag：根节点名称
    '''
    attrs = None#保存对象的属性集
    elelist = []#节点列表
    try:
      attrs = classobj.__dict__.keys()#获取该对象的所有属性(即成员变量)
    except:
      print 'classToElements:传入的对象非法，不能正确获取对象的属性'
    if attrs != None and len(attrs) > 0:#属性存在
      for attr in attrs:
        attrvalue = getattr(classobj, attr)#属性值
        #属性节点
        attrE = ET.Element(attr)
        attrE.text = attrvalue
        #加入节点列表
        elelist.append(attrE)
    return elelist
  @staticmethod
  def classToXML(classobj,rootTag=None):
    '''''
    Python自定义模型类转换成xml，转换成功返回的是xml根节点，否则返回None
    classobj：对象的实例
    rootTag：根节点名称
    '''
    try:
      classname = classobj.__class__.__name__ #类名
      if rootTag != None:
        root = Converter.createRoot(rootTag)
      else:
        root = Converter.createRoot(classname)
      elelist = Converter.classToElements(classobj, rootTag)
      for ele in elelist:
        root.append(ele)
      return root
    except:
      print 'classToXML:转换出错，请检查的传入的对象是否正确'
      return None
  @staticmethod
  def collectionToXML(listobj,rootTag='list'):
    '''''
              集合（列表、元组、字典）转换为xml，转换成功返回的是xml根节点，否则返回None
    '''
    try:
      classname = listobj.__class__.__name__ #类名
      root = Converter.createRoot(rootTag)
      if isinstance(listobj, list) or isinstance(listobj, tuple):#列表或元组
        if len(listobj) >= 0:
          for obj in listobj:#迭代列表中的对象
            itemE = Converter.classToXML(obj)
            root.append(itemE)
      elif isinstance(listobj, dict):#字典
        if len(listobj) >= 0:
          for key in listobj:#迭代字典中的对象
            obj = listobj[key]
            itemE = Converter.classToXML(obj)
            itemE.set('key', key)
            root.append(itemE)
      else:
        print 'listToXML：转换错误，传入的对象：'+classname+'不是集合类型'
      return root
    except:
      print 'collectionToXML：转换错误，集合转换成xml失败'
      return None
if __name__ == '__main__':
  p1 = Person('dredfsam','男','133665')
  p2 = Person('dream','女','r')
  p3 = Person('得分','男','sdf')
  personList = {}
  personList['p1']= p1
  personList['p2']= p2
  personList['p3']= p3
#  personList.append(p1)
#  personList.append(p2)
#  personList.append(p3)
  root = Converter.collectionToXML(personList)
  print Converter.getXmlString(root)
#  plist = (p1,p2,p3)#{'name':'sdf'}
#  print type(plist)
#  print type(plist),isinstance(plist, list)

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