This article mainly introduces the relevant information about Java's detailed examples of generating random string arrays. It mainly uses the Collections.sort() method to sort the List of generic Strings. Friends who need it can refer to it
Java Detailed Example of Generating a Random String Array
Use the Collections.sort() method to sort a List whose generic type is String. Specific requirements:
1. After creating List
2. The length of each string is a random integer within 10
3. Each Each character of the string is a randomly generated character, and the characters can overlap
4. Each random string cannot be repeated
The knowledge involved is: String, StringBuffer, ListArray, Generics, Collections.sort, foreach, Random and other related knowledge can be regarded as a relatively good practice in the JAVA learning process.
1. Randomly generate a character
1.1 First store all letters and numbers 0-9 in a string for subsequent use.
String str = "aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStT uUvVwWxXyYzZ0123456789";
1.2 To satisfy the randomness, create a Random object and use the nextInt(str.length) method to generate a 0 — str.length random number.
Random random = new Random(); int index = random.nextInt(str.length());
1.3 Then use the random number generated above as the index of the str string to retrieve the corresponding character, and randomly generate a character
char c = str.charAt(index);
2. Generate a random string with a length within 10
2.1 Because it is within 10 and meets randomness, here Use the Math.random() function, whose return value is a random Double type number from 0.0 to 1.0
StringBuffer stringBuffer = new StringBuffer(); //确定字符串长度 int stringLength = (int) (Math.random()*10);
2.2 Now the length of the string can be confirmed, and Generate random characters, and then use the for loop to generate a random string with a length of less than 10
for (int j = 0; j < stringLength; j++) { int index = random.nextInt(str.length()); char c = str.charAt(index); stringBuffer.append(c); } //将StringBuffer转换为String类型的字符串 String string = stringBuffer.toString();
3. Generate 10 Random string
3.1 After the above two steps, and then nesting a for loop outside, 10 random strings can be generated
4. Create a ListArray
4.1 Create a String type collection, this step should be completed simultaneously with Step 3
List<String> listString = new ArrayList<String>();
4.2 Add a string generated each time to the set. Pay attention to using the Contains() method of the set to determine whether the same string already exists in the set (although the probability is very small).
//判断当前的list容器中是否已有刚生成的字符串,满足每条字符串不可重复性 if(!(listString.contains(stringBuffer.toString()))){ listString.add(stringBuffer.toString()); }else { //i-- 如果不满足则重新生成 i--; }
5 Finally sort the collection
5.1 Call the Collections.sort() method to sort the collection. The rules are as follows:
principle from left to right, and 0-9
number priority principle, and A-Z
Capital letters take precedence, and a-z
##Total code
import java.util.ArrayList; import java.util.Collection; import java.util.Collections; import java.util.List; import java.util.Random; public class RandomString { public static void main(String[] args) { ListstrList = randomString(); System.out.println("------随机生成的10条字符串-------"); for (String string : strList) { System.out.println(string); } System.out.println("------------排序后------------"); Collections.sort(strList); for (String string : strList) { System.out.println(string); } } public static List randomString(){ //将所有的大小写字母和0-9数字存入字符串中 String str = "aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ0123456789"; Random random = new Random(); List<String> listString = new ArrayList<String>(); String strArray[ ] = new String[10]; //生成10条长度为1-10的随机字符串 for (int i = 0; i < 10; i++) { StringBuffer stringBuffer = new StringBuffer(); //确定字符串长度 int stringLength = (int) (Math.random()*10); for (int j = 0; j < stringLength; j++) { //先随机生成初始定义的字符串 str 的某个索引,以获取相应的字符 int index = random.nextInt(str.length()); char c = str.charAt(index); stringBuffer.append(c); } //判断当前的list容器中是否已有刚生成的字符串,满足每条字符串不可重复性 if (!(listString.contains(stringBuffer.toString()))) { listString.add(stringBuffer.toString()); }else { i--; } } return listString; } }
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