python basic syntax

巴扎黑
Release: 2017-09-21 10:48:19
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The following editor will bring you an example of python basic grammar practice. The editor thinks it’s pretty good, so I’ll share it with you now and give it as a reference. Let’s follow the editor to take a look.

1. Print the multiplication table


#只打印结果
for i in range(1,10):
  for j in range(1,i+1):
    print(i*j,end=" ")
  print()
 
#打印算数表达式
for i in range(1,10):
  for j in range(1,i+1):
    print("{0}*{1} = {2:2}".format(j,i,i*j),end=" ")
    print()
 
1*1 = 1 
1*2 = 2 2*2 = 4 
1*3 = 3 2*3 = 6 3*3 = 9 
1*4 = 4 2*4 = 8 3*4 = 12 4*4 = 16 
1*5 = 5 2*5 = 10 3*5 = 15 4*5 = 20 5*5 = 25 
1*6 = 6 2*6 = 12 3*6 = 18 4*6 = 24 5*6 = 30 6*6 = 36 
1*7 = 7 2*7 = 14 3*7 = 21 4*7 = 28 5*7 = 35 6*7 = 42 7*7 = 49 
1*8 = 8 2*8 = 16 3*8 = 24 4*8 = 32 5*8 = 40 6*8 = 48 7*8 = 56 8*8 = 64 
1*9 = 9 2*9 = 18 3*9 = 27 4*9 = 36 5*9 = 45 6*9 = 54 7*9 = 63 8*9 = 72 9*9 = 81
 
#将打印矩阵转置一下
for i in range(1,10):
  print(" " *10*(i-1), end = " ")
  for j in range(i,10):
    print("{0}*{1} = {2:<2}".format(i,j,i*j),end=" ")
  print()
   
 1*1 = 1  1*2 = 2  1*3 = 3  1*4 = 4  1*5 = 5  1*6 = 6  1*7 = 7  1*8 = 8  1*9 = 9 
      2*2 = 4  2*3 = 6  2*4 = 8  2*5 = 10 2*6 = 12 2*7 = 14 2*8 = 16 2*9 = 18 
           3*3 = 9  3*4 = 12 3*5 = 15 3*6 = 18 3*7 = 21 3*8 = 24 3*9 = 27 
                4*4 = 16 4*5 = 20 4*6 = 24 4*7 = 28 4*8 = 32 4*9 = 36 
                     5*5 = 25 5*6 = 30 5*7 = 35 5*8 = 40 5*9 = 45 
                          6*6 = 36 6*7 = 42 6*8 = 48 6*9 = 54 
                               7*7 = 49 7*8 = 56 7*9 = 63 
                                    8*8 = 64 8*9 = 72 
                                         9*9 = 81
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2. Print a diamond (the number of lines is an odd number)


for i in range(-3,4):
  prespace=(-i if i<0 else i)
  print(" "*prespace + &#39;*&#39;*(7-2*prespace))
 
  *
 ***
 *****
*******
 *****
 ***
  *
 
 
 
#变形之打印一道闪电
while True:
  line_max = int(input("please input a odd number: "))
  if line_max % 2:
    break
range_num = (line_max + 1)//2
 
for i in range(-range_num+1,range_num):
  if i == 0:
    print(&#39;*&#39;*line_max)
  elif i > 0:
    print(&#39; &#39;*(range_num-1) + "*"*(range_num-i))
  else:
    print(&#39; &#39;*(-i) + &#39;*&#39;*(range_num+i))
 
  *
 **
 ***
*******
  ***
  **
  *
 
#变形之打印掏空的菱形
for i in range(-4,5):
  if i == -4 or i == 4:
    print(&#39;*&#39;*9)
  else:
    prespace=(-i+1 if i<0 else i+1)
    print("*"*prespace + &#39; &#39;*(9-2*prespace) + "*"*prespace)
 
*********
**** ****
***  ***
**   **
*    *
**   **
***  ***
**** ****
*********
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3. Print within 100 The Fibonacci sequence


f0, f1 = 0, 1
while f1 <= 100:
  print(f1, end = " ")
  t = f1
  f1 = t + f0
  f0 = t
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I don’t understand how to write it yet:


f0, f1 = 0, 1
while f1 <= 100:
  print(f1)
  f0, f1 = f1, f0 + f1 #python对这样的赋值怎样处理
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4. Find the 101st term of the Fibonacci sequence


##

f0, f1 = 0, 1
for i in range(3,102):
  t = f1
  f1 = t + f0
  f0 = t
else:
  print(f1)
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