In actual development work, we will always encounter business needs such as scrolling, paging, calendar and other display effects. For those who have been exposed to jQuery
and are familiar with the use of jQuery
, the first thing that comes to mind is definitely to look for existing jQuery
plug-ins to meet the corresponding display needs. There are a variety of jQuery
plug-ins to choose from for some components commonly used in current pages. There are also many websites on the Internet that specifically collect jQuery
plug-ins. Using the jQuery
plug-in can indeed bring convenience to our development work, but if you only use it simply and don’t understand the principles, you will encounter problems during use or customize the development of the plug-in. There will be many doubts. The purpose of this article is to quickly understand the development principles of jQuery
plug-ins and master the basic skills of jQuery
development.
Before developing jQuery plug-ins, you must first know two questions: What is a jQuery plug-in? How to use jQuery plug-in?
The first question, jQuery
plug-in is a method used to extend jQuery
prototype object. Simply put, jQuery
plug-in isjQuery
A method of the object. In fact, after answering the first question, you will know the answer to the second question. The way to use the jQuery
plug-in is to call the jQuery
object method.
Let’s look at an example first: $("a").css("color","red")
. We know that each jQuery
object will contain the DOM
operation method defined in jQuery
. Here, the $ method is used to select the a element and return an ## of the a element. #jQuery object, this object can use the
DOM operation method defined in
jQuery. So how does the
jQuery object obtain these methods? In fact,
jQuery internally defines a
jQuery.fn object. Looking at the
jQuery source code, you can find
jQuery.fn=jQuery.prototype, that is It is said that the
jQuery.fn object is the prototype object of
jQuery, and the
DOM operation methods of
jQuery are all in
jQuery.fnDefined on the object, then the
jQuery object can inherit these methods through the prototype.
jQuery plug-in. If I now need a
jQuery plug-in to change the color of the label content, I can implement the plug-in in the following way:
$.fn.changeStyle = function(colorStr){ this.css("color",colorStr); }
$("p").changeStyle("red");
jQuery object currently calling the plug-in. In this case, each tag selected using the
$() method will be called
changeStyle()When plug-in, the
css() method will be used to reset the
color style.
jQuery, a general plug-in should follow
jQuery style, meeting the requirements of chain calls. The way to implement chain calling is also very simple:
$.fn.changeStyle = function(colorStr){ this.css("color",colorStr); return this; }
$("p").changeStyle("red").addClass("red-color");
return this, this line of code is added to the plug-in, then after the plug-in is executed, the current
jQuery object will be returned, and then you can continue to call other
jQuery after the plug-in method method.
$ symbol, although
jQuery You can use the
jQuery.noConflict() method to hand over the right to use the
$ symbol, but if you define a plug-in, use the
$.fn object to define it, Then when these plug-ins are used, they will be affected by other
js libraries that use
$ variables. In this case, we can use the immediate execution function to encapsulate the plug-in by passing parameters. The form is as follows:
(function($){ $.fn.changeStyle = function(colorStr){ this.css("color",colorStr); return this; } }(jQuery));
$ symbol can be avoided.
(function($){ $.fn.changeStyle = function(colorStr,fontSize){ this.css("color",colorStr).css("fontSize",fontSize+"px"); return this; } }(jQuery));
(function($){ $.fn.changeStyle = function(option){ this.css("color",option.colorStr).css("fontSize",option.fontSize+"px"); return this; } }(jQuery));
$("p").changeStyle({colorStr:"red",fontSize:14});
Put Another advantage of putting the parameters in an object and passing them to the plug-in is that we can define some default values for some parameters inside the plug-in, for example:
(function($){ $.fn.changeStyle = function(option){ var defaultSetting = { colorStr:"green",fontSize:12}; var setting = $.extend(defaultSetting,option); this.css("color",setting.colorStr).css("fontSize",setting.fontSize+"px"); return this; } }(jQuery));
上面的代码用到了$.extend
方法,这个方法在这里的用法就是合并两个对象,即把后面一个对象的存在的属性值赋值给第一个对象,具体用法可以参考这里。$.extend
方法还有一种作用是用来扩展jQuery
对象本身。
这样定义的插件,我们在使用时如果不传fontSize
,那么使用这个插件的jQuery
对象标签的内容会被设置成默认的12px
。
使用方式: $("p").changeStyle({colorStr:"red"});
注意:在为插件定义默认参数时,一定要把默认参数写在插件方法内部,这样默认参数的作用域就在插件内部。
定义插件的方式除了上面说的用$.fn
来定义,还有另外一种方式来定义插件,那就是使用$.fn.extend
方法。类似下面的写法:
//注意为了更好的兼容性,开始前有个分号;(function($){ $.fn.extend({ changeStyle:function(option){ var defaultSetting = { colorStr:"green",fontSize:12}; var setting = $.extend(defaultSetting,option); this.css("color",setting.colorStr).css("fontSize",setting.fontSize+"px"); return this; } }); }(jQuery));//这里将Jquery作为实参传递给匿名函数
PS: $.extend
方法和$.fn.extend
方法都可以用来扩展jQuery
功能,通过阅读jQuery
源码我们可以发现这两个方法的本质区别,那就是$.extend
方法是在jQuery
全局对象上扩展方法,$.fn.extend
方法是在$选择符选择的jQuery
对象上扩展方法。所以扩展jQuery
的公共方法一般用$.extend
方法,定义插件一般用$.fn.extend
方法。
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